[英]Android JSON Parsing with multiple arrays
我需要解析具有多個數組的JSON文件。 數組的格式為:
{
"List": {
"Something": [
{
"Name": "John",
"phone": "test"
}
]
"SomethingElse": [
{
"Name": "Smith",
"phone": "test"
}
]
}
}
問題是我不知道下一個數組名稱是什么。 是否可以解析所有數組中的數據而無需其名稱和不更改其結構?
謝謝。
JSON格式
{
"data": {
"current_condition": [
{
"cloudcover": "25",
"humidity": "62",
"observation_time": "04:57 PM",
"precipMM": "0.1",
"pressure": "1025",
"temp_C": "10",
"temp_F": "50",
"visibility": "10",
"weatherCode": "113",
"weatherDesc": [
{
"value": "Clear"
}
]
}
]
}
}
獲得“ weatherDesc”的價值
private class DownloadJSON extends AsyncTask<Void, Void, Void> {
@Override
protected void onPreExecute() {
super.onPreExecute();
// Create a progressdialog
mProgressDialog = new ProgressDialog(MainActivity.this);
// Set progressdialog title
mProgressDialog.setTitle("Android JSON Parse Tutorial");
// Set progressdialog message
mProgressDialog.setMessage("Loading...");
mProgressDialog.setIndeterminate(false);
// Show progressdialog
mProgressDialog.show();
}
@Override
protected Void doInBackground(Void... params) {
// Create an array
arraylist = new ArrayList<HashMap<String, String>>();
// Retrieve JSON Objects from the given URL address
jsonobject = JSONfunctions
.getJSONfromURL("http://api.worldweatheronline.com/free/v1/weather.ashx?q=London&format=json&num_of_days=5&key=8mqumbup9fub7bcjtsxbzxx9");
try {
// Locate the array name in JSON
JSONObject on=jsonobject.getJSONObject("data");
jsonarray = on.getJSONArray("current_condition");
for (int i = 0; i < jsonarray.length(); i++) {
HashMap<String, String> map = new HashMap<String, String>();
jsonobject = jsonarray.getJSONObject(i);
JSONArray sen1=jsonobject.getJSONArray("weatherDesc");
// Retrive JSON Objects
for(int j=0;j<sen1.length();j++){
jsonobject2 = sen1.getJSONObject(j);
map.put("value0", jsonobject2.getString("value"));
map.put("value1",jsonobject2.getString("value"));
map.put("flag", null);
// Set the JSON Objects into the array
arraylist.add(map);
}
}
} catch (JSONException e) {
Log.e("Error", e.getMessage());
e.printStackTrace();
}
return null;
}
@Override
protected void onPostExecute(Void args) {
// Locate the listview in listview_main.xml
listview = (ListView) findViewById(R.id.listview);
// Pass the results into ListViewAdapter.java
adapter = new ListViewAdapter(MainActivity.this, arraylist);
// Set the adapter to the ListView
listview.setAdapter(adapter);
// Close the progressdialog
mProgressDialog.dismiss();
}
}
嘗試這個
我寫了一個函數來遞歸地迭代JsonObject,卻不知道鍵名。
private void parseJson(JSONObject data) {
if (data != null) {
Iterator<String> it = data.keys();
while (it.hasNext()) {
String key = it.next();
try {
if (data.get(key) instanceof JSONArray) {
JSONArray arry = data.getJSONArray(key);
int size = arry.length();
for (int i = 0; i < size; i++) {
parseJson(arry.getJSONObject(i));
}
} else if (data.get(key) instanceof JSONObject) {
parseJson(data.getJSONObject(key));
} else {
System.out.println("" + key + " : " + data.optString(key));
}
} catch (Throwable e) {
System.out.println("" + key + " : " + data.optString(key));
e.printStackTrace();
}
}
}
}
Something
值后的JSON中缺少逗號,但是除此之外,您可以使用任何JSON解析器對其進行解析。
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