MySQL在一個查詢中多項選擇

Question

例如，我有幾個表：
產品介紹：

| product_id | name   | price |
| 1          | apple  | 20.32 |
| 2          | pear   | 9.99  |
| 3          | banana | 1.5   |

產品屬性：

| attr_id | name   | value |
| 1       | weight | 10 kg |
| 2       | date   | 2013  |
| 3       | color  | red   |

...等等。
最后產品-屬性關系表：

| product_id | attr_id |
| 1          | 3       |
| 2          | 1       |
| 1          | 2       |
| 3          | 2       |

我的問題：是否存在可用的構造一選擇請求查詢，該查詢在以下數據結構（或類似數據）中返回產品1和2？ 現在，我應該先運行deveral選擇請求“ where product_id IN（1、2）”，然后遍歷循環選擇它們的屬性。
對不起，英語不好：]

array(
    [0] = array(
          product_id = 1,
          name = apple,
          attributes= array(
                        [0] => array(
                           attr_id = 3,
                           name = color,
                           value = red,
                        ),
                        [0] => array(
                           attr_id = 2,
                           name = date,
                           value = 2013,
                        ) 

                      ),
    ),
    [1] = array(
          product_id = 2,
          name = apple,
          attributes= array(
                        [0] => array(
                           attr_id = 1,
                           name = veight,
                           value = 10 kg,
                        ),
                      ),
    )  
)

Answer 1

這不僅與查詢有關，還與PHP代碼有關。 這將適合：

$rSelect = mysqli_query('SELECT
     products.id AS record_id,
     products.name AS products_name,
     products.price AS product_price, 
     attributes.id AS attribute_id,
     attributes.name AS attribute_name,
     attributes.value AS attribute_value
   FROM
     products 
     LEFT JOIN products_attributes
       ON products.id=products_attributes.product_id
     LEFT JOIN attributes
       ON products_attributes.attr_id=attributes.id', $rConnect);

$rgResult = [];
while($rgRow = mysqli_fetch_array($rSelect))
{
   $rgResult[$rgRow['record_id']]['product_id']   = $rgRow['record_id'];
   $rgResult[$rgRow['record_id']]['name']         = $rgRow['product_name'];
   $rgResult[$rgRow['record_id']]['price']        = $rgRow['product_price'];
   $rgResult[$rgRow['record_id']]['attributes'][] = [
      'attr_id' => $rgRow['attribute_id'],
      'name'    => $rgRow['attribute_name'],
      'value'   => $rgRow['attribute_value'],
   ];
};
//var_dump($rgResult);

Answer 2

您要查找的查詢是：

select
    p.product_id,
    p.name as product_name,
    a.attr_id,
    a.name as attr_name,
    a.value
from
    products as p
    inner join `product-attribute` as pa on p.id = pa.product_id
    inner join attribute as a on pa.attr_id = a.attr_id

這將返回一個簡單的結果表，您可以在其中創建多維數組。

您可能會在此查詢中注意到兩件事：

• 我在表名稱product-attribute周圍使用反引號` ，因為它在名稱中包含一個破折號-這是保留名稱。 因此，您需要將其放在反引號中以避開該名稱。
• 因為字段名稱name不明確，所以我給它們起了一個別名（ product_name / attr_name ），以便以后仍可以用別名來引用它們。