簡體   English   中英

休眠與n個級別的關聯

[英]hibernate association with n levels

我有兩個表(ProspectMaster,ProspectContactsMaster)。 為了維護關系,我使用可嵌入實體(ProspectContactsMapID)制作了一個映射表(ProspectContactsMap)。 波紋管是所有實體

@Entity
public class ProspectMaster {

    @Id
    @GeneratedValue(strategy = GenerationType.AUTO)
    private int prospectID;

    @Column(nullable=false)
    @Length(max = 50)
    private String companyName;

    @OneToMany(fetch = FetchType.LAZY, mappedBy = "prospectContactsMapID.prospectMaster", cascade=CascadeType.ALL)
    private Set<ProspectContactsMap> prospectContactsMap = new HashSet<ProspectContactsMap>(0);

    public int getProspectID() {
        return prospectID;
    }

    public void setProspectID(int prospectID) {
        this.prospectID = prospectID;
    }

    public String getCompanyName() {
        return companyName;
    }

    public void setCompanyName(String companyName) {
        this.companyName = companyName;
    }

    public Set<ProspectContactsMap> getProspectContactsMap() {
        return prospectContactsMap;
    }

    public void setProspectContactsMap(Set<ProspectContactsMap> prospectContactsMap) {
        this.prospectContactsMap = prospectContactsMap;
    }

}

@Entity
public class ProspectContactsMaster {
    @Id
    @GeneratedValue(strategy = GenerationType.AUTO)
    private int prospectContactID;

    @Length(max = 25)
    private String firstName;

    public int getProspectContactID() {
        return prospectContactID;
    }

    public void setProspectContactID(int prospectContactID) {
        this.prospectContactID = prospectContactID;
    }

    public String getFirstName() {
        return firstName;
    }

    public void setFirstName(String firstName) {
        this.firstName = firstName;
    }
}

@Entity
@AssociationOverrides({
    @AssociationOverride(name = "prospectContactsMapID.prospectMaster", 
        joinColumns = @JoinColumn(name = "prospectID")),
    @AssociationOverride(name = "prospectContactsMapID.prospectContactsMaster", 
        joinColumns = @JoinColumn(name = "prospectContactID")) })
public class ProspectContactsMap {

    @EmbeddedId
    private ProspectContactsMapID prospectContactsMapID = new ProspectContactsMapID();

    private int isMainContact;

    @Transient
    public ProspectMaster getProspectMaster() {
        return this.getProspectContactsMapID().getProspectMaster();
    }

    public void setProspectMaster(ProspectMaster prospectMaster) {
        getProspectContactsMapID().setProspectMaster(prospectMaster);
    }

    @Transient
    public ProspectContactsMaster getProspectContactsMaster() {
        return this.getProspectContactsMapID().getProspectContactsMaster();
    }

    public void setProspectContactsMaster(ProspectContactsMaster prospectContactsMaster) {
        getProspectContactsMapID().setProspectContactsMaster(prospectContactsMaster);
    }

    public ProspectContactsMapID getProspectContactsMapID() {
        return prospectContactsMapID;
    }

    public void setProspectContactsMapID(ProspectContactsMapID prospectContactsMapID) {
        this.prospectContactsMapID = prospectContactsMapID;
    }

    public int getIsMainContact() {
        return isMainContact;
    }

    public void setIsMainContact(int isMainContact) {
        this.isMainContact = isMainContact;
    }

}

@Embeddable
public class ProspectContactsMapID implements Serializable {
    @ManyToOne
    private ProspectMaster prospectMaster;

    @ManyToOne
    private ProspectContactsMaster prospectContactsMaster;

    public ProspectMaster getProspectMaster() {
        return prospectMaster;
    }

    public void setProspectMaster(ProspectMaster prospectMaster) {
        this.prospectMaster = prospectMaster;
    }

    public ProspectContactsMaster getProspectContactsMaster() {
        return prospectContactsMaster;
    }

    public void setProspectContactsMaster(ProspectContactsMaster prospectContactsMaster) {
        this.prospectContactsMaster = prospectContactsMaster;
    }
}

現在,我的要求是獲取公司名稱以d開頭或主要聯系人以d開頭的所有潛在客戶。 我進行了查詢,但是在n級我無法提供關聯屬性。 波紋管是我的查詢

Disjunction disjOrCondition = Restrictions.disjunction(); 
Criteria cr = getCurrentSession().createCriteria(ProspectMaster.class);
cr.createAlias("prospectContactsMap", "prospectContact");

Criterion thirdCondition = Restrictions.conjunction().add(Restrictions.eq("prospectContact.isMainContact",1))
    .add(Restrictions.like("prospectContact.prospectContactsMapID.prospectContactsMaster.firstName", searchVal.toString(),MatchMode.ANYWHERE));
disjOrCondition.add(Restrictions.like("companyName", searchVal.toString(),MatchMode.ANYWHERE));
disjOrCondition.add(thirdCondition);

如果運行此命令,則會出現以下異常

org.hibernate.QueryException: could not resolve property: prospectContactsMapID.prospectContactsMaster.firstName

誰能告訴我問題出在哪里? 誰能告訴我任何相同的例子。 我只想使用hql。

據我所知,我只能告訴你兩件事:

  • 您可以嘗試另一種獲取策略; 而不是LAZY,您可以嘗試EAGER

  • 配置文件中有一個屬性: hibernate.max_fetch_depth ,但是我想您使用的是默認設置。 它設置單端關聯的最大深度。

暫無
暫無

聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.

 
粵ICP備18138465號  © 2020-2024 STACKOOM.COM