[英]Traverse JSON object in Javascript?
下面是我的代碼。 請幫助我循環瀏覽。 我想循環播放完整的JSON並進行一些驗證,但是我無法循環通過它。 我是第一次這樣做,如果any1可以幫助我,那就太好了。
有什么辦法可以過濾JSON對象。 例如,我要搜索audit1的asgn值。 filter可以是動態的,就像可以是audit1或audit11。 我也想知道如何將上述json轉換為數組。 這將使我的搜索變得容易(如果無法通過直接JSON搜索進行搜索)。
function fnMultiRowValidation(){
var vStatus = 5,
vJson = '{"tpaCo":[{"name":"Audit Company1",\
"aud":[{"name":"auditor1","asgn":"1","fnds":"1","lead":"1"},\
{"name":"auditor2","asgn":"1","fnds":"0","lead":"1"},\
{"name":"auditor3","asgn":"0","fnds":"1","lead":"0"},\
{"name":"auditor4","asgn":"1","fnds":"1","lead":"0"},\
{"name":"auditor5","asgn":"1","fnds":"1","lead":"0"},\
{"name":"auditor6","asgn":"0","fnds":"1","lead":"0"},\
{"name":"auditor7","asgn":"1","fnds":"1","lead":"0"},\
{"name":"auditor8","asgn":"1","fnds":"1","lead":"0"},\
{"name":"auditor9","asgn":"0","fnds":"1","lead":"0"},\
{"name":"auditor10","asgn":"1","fnds":"1","lead":"0"},\
{"name":"auditor11","asgn":"1","fnds":"1","lead":"0"}]},\
{"name":"Audit Company2",\
"aud":[{"name":"auditor3","asgn":"1","fnds":"1","lead":"1"},\
{"name":"auditor4","asgn":"1","fnds":"1","lead":"0"}\
]\
}\
]}';
var vObj = JSON.parse(vJson);
for (var i=0;i<vObj.tpaCo.length;i++){
$.each(vObj.tpaCo[i], function(key, value) {
console.log(key +':'+ value);
if(typeof(value)=='object'){
//console.log('Auditor length:'+vObj.tpaCo.value.length);
}
});
}
}
vObj.tpaCo.value.length
將無法正常工作。 您必須使用vObj.tpaCo[key].length
或value.length
。 對於初學者,您不應在each
迭代中都混入本機for循環。
for (var i=0; i<vObj.tpaCo.length; i++) { // iterate through outer array
for (var key in vObj.tpaCo[i]) { // enumerate item keys
console.log(key +':'+ vObj.tpaCo[i][key]); // logs "name" and "aud"
}
console.log('Auditor length:'+vObj.tpaCo[i].aud.length);
for (var j=0; j<vObj.tpaCo[i].aud.length; j++) { // iterate "aud" array
console.log(vObj.tpaCo[i].aud[j].name);
}
}
通過使用變量簡化:
var tpacos = vObj.tpaCo;
for (var i=0; i<tpacos.length; i++) {
var comp = tpacos[i];
for (var key in comp) {
var value = comp[key];
console.log(key +':'+ value);
}
var auds = comp.aud;
console.log('Auditor length:'+auds.length);
for (var j=0; j<auds.length; j++) {
var aud = auds[j];
console.log(aud.name);
}
}
現在使用Array forEach
方法 :
vObj.tpaCo.forEach(function(comp, i) {
for (var key in comp) {
var value = comp[key];
console.log(key +':'+ value);
}
console.log('Auditor length:'+comp.aud.length);
comp.aud.forEach(function(aud, j) {
console.log(aud.name);
});
});
和jQuery的each
:
$.each(vObj.tpaCo, function(i, comp) {
$.each(comp, function(key, value) {
console.log(key +':'+ value);
});
console.log('Auditor length:'+comp.aud.length);
$.each(comp.aud, function(j, aud) {
console.log(aud.name);
});
});
您的代碼應該像這樣
$.each(vObj.tpaCo, function(key, value) {
console.log(key +':'+ value);
if(typeof(value)=='object'){
//console.log('Auditor length:'+vObj.tpaCo.value.length);
}
});
希望能幫助到你.....
function fnMultiRowValidation(){
var vStatus = 5,
vJson = '{"tpaCo":[{"name":"Audit Company1",\
"aud":[{"name":"auditor1","asgn":"1","fnds":"1","lead":"1"},\
{"name":"auditor2","asgn":"1","fnds":"0","lead":"1"},\
{"name":"auditor3","asgn":"0","fnds":"1","lead":"0"},\
{"name":"auditor4","asgn":"1","fnds":"1","lead":"0"},\
{"name":"auditor5","asgn":"1","fnds":"1","lead":"0"},\
{"name":"auditor6","asgn":"0","fnds":"1","lead":"0"},\
{"name":"auditor7","asgn":"1","fnds":"1","lead":"0"},\
{"name":"auditor8","asgn":"1","fnds":"1","lead":"0"},\
{"name":"auditor9","asgn":"0","fnds":"1","lead":"0"},\
{"name":"auditor10","asgn":"1","fnds":"1","lead":"0"},\
{"name":"auditor11","asgn":"1","fnds":"1","lead":"0"}]},\
{"name":"Audit Company2",\
"aud":[{"name":"auditor3","asgn":"1","fnds":"1","lead":"1"},\
{"name":"auditor4","asgn":"1","fnds":"1","lead":"0"}\
]\
}\
]}';
var vObj = JSON.parse(vJson);
$.each(vObj.tpaCo, function(key, value) {
console.log(value.name);
});
}
刪除循環。 使用此腳本
要獲取aud元素,您需要在當前循環中具有$ .each函數
我很確定您可以擺脫for
循環,而只需使用
$.each( vObk.tpaCo, function(key, value) {
console.log(key + ':' + value);
//... do stuff with value ...
})
$.each(vObj.tpaCo, function(key, value) {
console.log(value.name+" ")
for(i=0; i<value.aud.length; i++)
console.log(value.aud[i]);
});
或者如果您不知道名字
$.each(vObj, function(key, value){
$.each(value, function(key, value){
for(val in value)
if(typeof val == 'string')
console.log(value[val]
else
for(i=0; i<value[val].length ; i++)
console.log(value[val][i]);
});
});
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