[英]Django Import Class From models.py
使用這樣的文件夾結構:
library/
-django.wsgi
-manage.py
-static/
--all my static files
-library/
--__init__.py
--models.py
--settings.py
--urls.py
--views.py
--wsgi.py
--templates/
---where i plan to store all my templates
如何在models.py中定義的views.py中導入類?
我試過了:
from . import models.class
from models import class
from projectname.models import class
from projectname import models.class
from project import class
但對於所有那些我得到無效的語法錯誤
views.py
from django.core.context_processors import csrf
from django.shortcuts import redirect, render
from django.contrib.auth import authenticate, login
from django.contrib.auth.decorators import login_required
from django.contrib.auth.models import User
from django.http import HttpResponse
from django.contrib import messages
from django.template import RequestContext, loader
from django.contrib.auth import logout
from library.models import 7DTagmap
models.py
from __future__ import unicode_literals
from django.db import models
class 7DTagmap(models.Model):
id = models.IntegerField(primary_key=True)
tag_id = models.CharField(max_length=50L)
st_tag_id = models.IntegerField()
class Meta:
db_table = '7d_tagmap'
錯誤:
invalid syntax (views.py, line 11)
Exception Type: SyntaxError
Exception Value: invalid syntax (views.py, line 11)
采用:
from library.models import MyClass
你應該好好去:)
(基本結構from <app>.models import <ModelName>
)
更新:
問題是(幾乎!)肯定你的模型以'7'開頭 - 把它改成字母字符,一切都會好的,我(差不多!)肯定:)
例如,在你的models.py
你得到了:
from django.db import models
from django.contrib.auth.models import User
class register(models.Model):
user = models.OneToOneField(User)
然后在views.py
,你可以像這樣調用:
from library.models import register
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