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僅從兩個表查詢中選擇最高結果

[英]Selecting only top result from two table query

這是我的兩個表:
歌曲:

+--------+---------------------+
| SongID |    SongDeviceID     |
+--------+---------------------+
|   3278 | 1079287588763212246 |
|   3279 | 1079287588763212221 |
|   3280 | 1079287588763212230 |
+--------+---------------------+

投票:

+--------+--------+
| SongID | UserID |
+--------+--------+
|   3278 |     71 |
|   3278 |     72 |
|   3279 |     71 |
+--------+--------+

我試圖計算votes表中的條目votes (對於每個唯一的SongID並返回SongDeviceID的條目的SongDeviceID

這是我到目前為止:

SELECT Songs.SongDeviceID, COUNT(*) FROM Votes INNER JOIN Songs ON Votes.SongID = Songs.SongId GROUP BY Votes.SongID, Songs.SongDeviceID ORDER BY count(*) DESC

哪個回報:

+---------------------+----------+
|    SongDeviceID     | Count(*) |
+---------------------+----------+
| 1079287588763212246 |        2 |
| 1079287588763212221 |        1 |
+---------------------+----------+

更新:查詢已更新,以處理獲取SongDeviceID但我仍然需要幫助只返回第一行。

首先

SELECT  SongID,COUNT(*) from votes GROUP BY SongID order by count(*) DESC LIMIT 1

然后你想要歌曲設備名稱

SELECT SongID,COUNT(*),SongDeviceID
from
  votes 
left join 
   Songs on votes.songid = song.songid
GROUP BY
   SongID 
order by 
   count(*) DESC LIMIT 1

嘗試這個

   SELECT Songs.SongDeviceID, COUNT(*) FROM Votes INNER JOIN Songs ON Votes.
    SongID =  Songs.SongId GROUP BY Votes.SongID, Songs.SongDeviceID ORDER BY count(*) 
    DESC LIMIT 1
select top 1
    S.SongDeviceID, COUNT(distinct V.UserID) as 'UserVotes'
from
   Songs as S
join 
  Votes as V on V.SongID = S.SongID
group by
   S.SongDeviceID
order by
  UserVotes DESC

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