如何在onTouch函數中使用while循環？ （機器人）

Question

好吧，我一直在查找答案，但沒有一個對我有用。 我有一個按鈕，當它是HELD DOWN時，假設繼續在屏幕上移動圖像。 但出於某種原因，當我點擊按鈕時它只會讓我的點燃。 我認為線程是問題的一部分，但我不確定。 這是代碼：

package com.evilsea.darkages;

import android.os.Bundle;
import android.app.Activity;
import android.graphics.Color;
import android.view.MotionEvent;
import android.view.View;
import android.view.View.OnTouchListener;
import android.widget.ImageView;

public class MainActivity extends Activity implements OnTouchListener, Runnable {

ImageView leftImageButton;

boolean leftButtonDown = false;

ImageView knight;

@Override
public void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);
    Thread thread1 = new Thread(this);
    thread1.start();
    this.run();
}

public void addListenerOnLeftButton() {

    leftImageButton = (ImageView) findViewById(R.id.left_button);
    leftImageButton.setOnTouchListener(leftButtonlistener);

    knight = (ImageView) findViewById(R.id.knight_image);

}

OnTouchListener leftButtonlistener = new OnTouchListener() {
    @Override
    public boolean onTouch(View view, MotionEvent event) {
        switch (event.getAction()) {

            case MotionEvent.ACTION_DOWN:
                leftButtonDown = true;
            try {
                while(leftButtonDown) {
                    Thread.sleep(10);
                    moveLeft(5);
                }
            } catch (InterruptedException e) {
                e.printStackTrace();
            }
            break;

            case MotionEvent.ACTION_UP:
                leftButtonDown = false;
            break;
        }

        return false;
    }
    };

@Override
public boolean onTouch(View v, MotionEvent event) {
    // TODO Auto-generated method stub
    return false;
}

@Override
public void run() {
    addListenerOnLeftButton();
}

public void moveLeft(int speed) throws InterruptedException {
    knight.setLeft(knight.getLeft() -speed);
}

}

順便說一句，我剛剛開始使用android，所以如果這是一個明顯的問題，我很抱歉。 謝謝！ 非常感激。

Answer 1

首先，你正在進行UI線程休眠，這就是你的UI被凍結的原因。在這里，我創建了一個異步任務，我正在睡覺后台線程並在主線程上運行UI更新，如下面doInBackground方法中所示。這是你的解決方案 - ：

public class MainActivity extends Activity {

    private ImageView leftImageButton;
    private boolean leftButtonDown = false;
    private ImageView knight;
    private AsyncTask asyncTask = null;

    @Override
    public void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_main);

        leftImageButton = (ImageView) findViewById(R.id.imageView2);
        knight = (ImageView) findViewById(R.id.imageView1);
        leftImageButton.setOnTouchListener(new LeftImageListener());
    }

    public void startTask() {
        asyncTask = new AsyncTask<Void, Void, Void>() {

            @Override
            protected Void doInBackground(Void... params) {
                if (leftButtonDown) {
                    while (leftButtonDown) {
                        try {
                            Thread.sleep(10);
                            runOnUiThread(new Runnable() {

                                @Override
                                public void run() {
                                    try {
                                        moveLeft(5);

                                    } catch (InterruptedException e) {
                                        // TODO Auto-generated catch block
                                        e.printStackTrace();
                                    }

                                }
                            });

                        } catch (InterruptedException e) {
                            e.printStackTrace();
                        }
                    }
                }
                return null;
            }

        }.execute();
    }

    public void moveLeft(int speed) throws InterruptedException {
        knight.setLeft(knight.getLeft() - speed);
    }

    public class LeftImageListener implements OnTouchListener {

        public LeftImageListener() {
            // TODO Auto-generated constructor stub
        }

        @Override
        public boolean onTouch(View v, MotionEvent event) {

            switch (event.getAction()) {
            case MotionEvent.ACTION_DOWN:
                leftButtonDown = true;
                startTask();
                break;
            case MotionEvent.ACTION_UP:
                leftButtonDown = false;
                break;
            default:
                break;
            }

            return true;
        }

    }

}

Answer 2

創建第二個線程是正確的，但你應該用一些動作填充它，因為你創建的線程是空的:)並且你不需要在啟動你的線程后調用run。

Thx Abhishek Birdawade為我做代碼工作:)