[英]Broadcast receiver in an activity
嗨,我正在開發一個android SMS應用程序,其中我在活動中使用廣播接收器,並參考以下鏈接,
我已經嘗試過此代碼
public class Myapp extends Activity
{
BroadcastReceiver sendBroadcastReceiver= new sentReceiver();
protected void onCreate(Bundle savedInstanceState)
{
super.onCreate(savedInstanceState);
setContentView(R.layout.activtiy_main);
}
public void onClick(View v)
{
if(v.getId()==sendmsg.getId())
{
sendSMS(phoneNumber,message);
}
@Override
protected void onDestroy()
{
super.onDestroy();
try
{
unregisterReceiver(sendBroadcastReceiver);
}
catch (Exception e)
{
e.printStackTrace();
}
}
//unregistering Receiver even in onPause()
private void sendSMS(String phoneNumber, String message)
{
String SENT = "SMS_SENT";
PendingIntent sentPI = PendingIntent.getBroadcast(this, 0, new Intent(SENT), 0);
registerReceiver(sendBroadcastReceiver, new IntentFilter(SENT));
SmsManager sms = SmsManager.getDefault();
sms.sendTextMessage(phoneNumber, null, message, sentPI, null);
}
class sentReceiver extends BroadcastReceiver
{
@Override
public void onReceive(Context context, Intent arg1)
{
switch (getResultCode())
{
case Activity.RESULT_OK:
Toast.makeText(getBaseContext(), "sms_sent", Toast.LENGTH_SHORT).show();
startActivity(new Intent(Myapp.this, Sm.class));
break;
case SmsManager.RESULT_ERROR_NO_SERVICE:
Toast.makeText(getBaseContext(), "No service",Toast.LENGTH_SHORT).show();
Log.e("No service","");
break;
}
}
}
}
但是我收到警告
java.lang.IllegalArgumentException: Receiver not registered: com.example.Myapp$Receiver@40593ab8
不確定我需要如何在清單中注冊接收者。請提出建議。謝謝!
1.您正在以編程方式注冊接收器
registerReceiver(sendBroadcastReceiver, new IntentFilter(SENT));
因此,也無需將其添加到清單中。
2.您有一個名為“ sentReceiver”的自定義BroadcastReceiver類,因此在實例化該對象類型時應使用它。
所以你需要改變
BroadcastReceiver sendBroadcastReceiver= new sentReceiver();
至
SentReceiver sendBroadcastReceiver = new sentReceiver();
3.我認為您打錯電話的順序是正確的。 因此,接收器在應該收聽的時候還沒有准備好收聽。
您需要在活動的oncreate方法中實例化sendBroadcastReceiver。 在調用ondestroy方法並且您的代碼未注冊接收者之后,這將允許“重新注冊”。 就像Bofredo指出的那樣,使用您的自定義校准實例化。
聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.