[英]Call servlet from another servlet form tag
我有一個帶有表單標簽的Servlet。 在此表單標簽中,我想調用另一個servlet。
out.println("<form id=\"myform\" action='/SubmitHome' method=\"post\">");
因此,當我單擊提交按鈕時:
out.println("<input type=\"submit\" name=\"assignButton\" value=\"Assign\" />
它沒有調用“ / SubmitHome”。
知道為什么不打電話嗎?
請檢查您的HTML,標記是否正確關閉? 例如
<form action="" method="post">
<input type="submit" value="Submit">
</form>
Sytanx對於以下行是錯誤的(您需要完成println
大括號:
out.println("<input type=\\"submit\\" name=\\"assignButton\\" value=\\"Assign\\" />
應該
out.println("<input type=\\"submit\\" name=\\"assignButton\\" value=\\"Assign\\" />");
其他一切都完美無缺,並且運作良好:)
這是完成任務的示例代碼。
步驟1:創建一個Servlet。
package org.smarttechie;
import java.io.IOException;
import java.io.PrintWriter;
import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
/**
* Servlet implementation class SampleServlet1
*/
public class SampleServlet1 extends HttpServlet {
private static final long serialVersionUID = 1L;
/**
* @see HttpServlet#HttpServlet()
*/
public SampleServlet1() {
super();
// TODO Auto-generated constructor stub
}
/**
* @see HttpServlet#doGet(HttpServletRequest request, HttpServletResponse response)
*/
protected void service(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
PrintWriter out = response.getWriter();
out.println("<html><body>");
out.println("<form action=\"SampleServlet2\" method=\"get\">");
out.println("<input type=\"submit\" value=\"Submit\">");
out.println("</form>");
out.println("</body></html>");
}
}
步驟2:創建另一個Servlet。 這將從表單操作標簽中調用。 如果您觀察到表單操作標簽值,則指向“ SampleServlet2” URL模式(不包括“ /”)。 如果要給出絕對路徑(包括“ /”),我們需要指定上下文路徑。
package org.smarttechie;
import java.io.IOException;
import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
/**
* Servlet implementation class SampleServlet2
*/
public class SampleServlet2 extends HttpServlet {
private static final long serialVersionUID = 1L;
/**
* @see HttpServlet#HttpServlet()
*/
public SampleServlet2() {
super();
// TODO Auto-generated constructor stub
}
/**
* @see HttpServlet#doGet(HttpServletRequest request, HttpServletResponse response)
*/
protected void service(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
System.out.println("The request is reached");
}
}
步驟3:web.xml配置如下。
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" id="WebApp_ID" version="2.5">
<servlet>
<description></description>
<display-name>SampleServlet1</display-name>
<servlet-name>SampleServlet1</servlet-name>
<servlet-class>org.smarttechie.SampleServlet1</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>SampleServlet1</servlet-name>
<url-pattern>/SampleServlet1</url-pattern>
</servlet-mapping>
<servlet>
<description></description>
<display-name>SampleServlet2</display-name>
<servlet-name>SampleServlet2</servlet-name>
<servlet-class>org.smarttechie.SampleServlet2</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>SampleServlet2</servlet-name>
<url-pattern>/SampleServlet2</url-pattern>
</servlet-mapping>
</web-app>
希望這能解決您的問題。
您應該檢查web.xml中的url映射,這是表單未在所需頁面上提交的唯一原因。
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