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[英]subtract two different sum of column from two different table in select query
[英]sum two different table and the subtract its total
我對如何從兩個不同的表中求和,然后求和后總和我想減去它。 例如我有表“銷售”和“銷售”,我在下面有這些ff vlue。
來自“銷售”的數據
id | total | pcode |
1 | 100 | 2143 |
2 | 100 | 2143 |
3 | 50 | 2222 |
4 | 50 | 2222 |
來自“銷售”的數據
id | total | pcode |
7 | 100 | 2143 |
8 | 50 | 2222 |
我的問題是這個。 我想對所有來自銷售的“合計”值求和,並通過pcode。從rsales組求和“合計”值。 我的頁面必須是這樣的。
total pcode
| 100 | 2143 |
| 50 | 2222 |
我有這個ff代碼,但我不滿意
sql "select sum(rsales.total)- sum(sales.total) as t1 where pcode = rsales.pcode"
采用:
SELECT
SUM(r.total)-(
SELECT SUM(s.total)
FROM sales AS s WHERE r.pcode=s.pcode
) as total,
r.pcode
FROM rsales AS r
GROUP BY r.pcode;
輸出:
+--+--+--+--+--+-
| total | pcode |
+--+--+--+--+--+-
| 100 | 2143 |
| 50 | 2222 |
+--+--+--+--+--+-
2 rows in set
你嘗試過這樣的事情嗎?
SELECT
SUM(L.total) as lTotal, SUM(R.total) as rTotal
FROM
sales L
INNER JOIN rsales R
ON
R.pcode = L.pcode
GROUP BY L.pcode
如果從兩個表中都獲得期望值,則可以在FROM子句中輕松添加Additions和Subtruction。
無需加入即可執行此操作。 如果某些pcode僅在一個表中,則此解決方案有效:
select SUM(total), pcode from (
select sum(total) as total, pcode from rsales group by pcode
union all
select SUM(-total) as total, pcode from sales group by pcode) salesTables
group by pcode
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