PHP MySQL多維數組按條件日期排序

Question

我試圖按狀態為0（未分級的圖像）和狀態== 1（已 分級的圖像）的條件，在多維數組中按降序排列的修改日期（意味着最新的優先）進行排序。

是否有可能對數組進行排序，以使前2名遵循以下邏輯：

If (there are multiple versions of an image)
   If (there is a version that has been rated)
      If (there is a new unrated version of the image)
         Display (the most recent version that has a rating) and 
         (the most recent unrated version) as top 2 of array
      Else
         Display (the most recent version that has a rating) as top 1
   Else
      Display (the most recent unrated version) as top 1
Else
   Display (the only version) as top 1

---

這是下面我的更新PHP代碼（2013年9月6日更新） ：

updateImageDisplayStatus($caseID,$patientID);

function updateImageDisplayStatus($caseid,$patientid) {

$connection = getMySqlConnection();
$sql = "SELECT image_name FROM images WHERE patientid = '{$patientid}' AND caseid = '{$caseid}' ";

$imageGroup = array();
$result = mysql_query($sql,$connection);
while($row = mysql_fetch_assoc($result)) {

    $fileName =  $row['image_name'];
    $tmpName = $row['image_name'];
    list($leftN,$rightN) = explode($caseid."_",$tmpName);
    //$spltName = explode('_',$rightN);
    $shortFileName = $rightN;
    list($noExtensionFileName,$extension) = explode('.',$shortFileName);
    //$extension = '.nii.gz';
    list($groupName,$appendDate) = explode('_',$noExtensionFileName);
    // echo $groupName = just the original name.

  $sql_2 = "SELECT image1.image_name as i1_image_name
  ,image1.comments   as i1_comments
  ,image1.status     as i1_status
  ,image1.mod_date   as i1_mod_date
  ,image2.image_name as i2_image_name
  ,image2.comments   as i2_comments
  ,image2.status     as i2_status
  ,image2.mod_date   as i2_mod_date
  FROM (SELECT CASE WHEN status = 0 THEN 1 ELSE 0 END as rated
          ,image_name
          ,comments
          ,status
          ,mod_date
      FROM images
     WHERE image_name like '%{$groupName}%' 
     ORDER BY 1 ASC, mod_date DESC
     LIMIT 1
   ) image1
  LEFT OUTER
  JOIN images image2
    ON image1.status > 0
   AND image2.status = 0
   AND image2.mod_date > image1.mod_date
   AND image2.image_name like '%{$groupName}%'
      AND patientid = '{$patientid}' AND caseid = '{$caseid}'
 ORDER BY image2.mod_date DESC
 LIMIT 1";

$result_2 = mysql_query($sql_2,$connection);
if($row = mysql_fetch_assoc($result_2)) {
    $imageGroup[$groupName]   = array();
    $imageGroup[$groupName][] = array(
        'image_name'  => $row['i1_image_name'],
        'comments'    => $row['i1_comments'], 
        'status'      => $row['i1_status'],
        'mod_date'    => $row['i1_mod_date']
        );
    if ( !empty( $row['i2_image_name'] ) ) {
        $imageGroup[$groupName][] = array(
            'image_name'  => $row['i2_image_name'],
            'comments'    => $row['i2_comments'], 
            'status'      => $row['i2_status'],
            'mod_date'    => $row['i2_mod_date']
        );
    }
}
echo "Group $groupName:<br />";
echo "Size of Group:".sizeof($imageGroup[$groupName]).'<br />';

echo $imageGroup[$groupName][0]['image_name'].'<br />';
echo $imageGroup[$groupName][1]['image_name'].'<br />';
}
}

---

更新：

感謝@gwc提出讓SQL完成工作的建議。 我忘了補充說，搜索和排序的1-2張圖像必須在指定的$ caseid和$ Patientid之內。 結果，第一個sql語句應為： $sql = "SELECT image_name FROM images WHERE patientid = '{$patientid}' AND caseid = '{$caseid}' ";

Answer 1

更新了SQL以將其限制在同一患者和同一病例內

如果我正確理解了您的問題，則可以讓SQL為您完成工作。 無需循環或數組。 以下SQL應該返回一行。 不幸的是，我目前無法測試此方法，因此我希望SQL中沒有錯誤。 此SQL將替換您的$ sql_2：

SELECT image1.patientid
      ,image1.caseid
      ,image1.image_name as i1_image_name
      ,image1.comments   as i1_comments
      ,image1.status     as i1_status
      ,image1.mod_date   as i1_mod_date
      ,image2.image_name as i2_image_name
      ,image2.comments   as i2_comments
      ,image2.status     as i2_status
      ,image2.mod_date   as i2_mod_date
  FROM (SELECT CASE WHEN status = 0 THEN 1 ELSE 0 END as rated
              ,patientid
              ,caseid
              ,image_name
              ,comments
              ,status
              ,mod_date
          FROM images
         WHERE patientid  = '{$patientid}'
           AND caseid     = '{$caseid}'
           AND image_name like '%{$group_name}%'
         ORDER BY 1 ASC, mod_date DESC
         LIMIT 1
       ) image1
  LEFT OUTER
  JOIN images image2
    ON image1.status     > 0
   AND image2.patientid  = image1.patientid
   AND image2.caseid     = image1.caseid
   AND image2.status     = 0
   AND image2.mod_date   > image1.mod_date
   AND image2.image_name like '%{$group_name}%'
 ORDER BY image2.mod_date DESC
 LIMIT 1

返回的行包含10列：

• patientid
• 案例ID
• i1_image_name
• i1_comments
• i1_status
• i1_mod_date
• i2_image_name
• i2_comments
• i2_status
• i2_mod_date

i1_ *列來自第一張圖片，i2_ *列來自第二張圖片（如果有）。 如果存在額定圖像，則i1_ *將代表最近修改的額定圖像，而i2_ *將代表在i1_ *圖像之后修改的最近修改的未額定圖像。 如果沒有在額定圖像之后修改過的未額定圖像，則i2_ *將為NULL。 如果沒有評級圖像，則i1_ *將代表最近修改的未評級圖像，而i2_ *將為NULL。

更新

這是我看到它被使用的方式。

    $sql_2 = "SELECT image1.patientid
      ,image1.caseid
      ,image1.image_name as i1_image_name
      ,image1.comments   as i1_comments
      ,image1.status     as i1_status
      ,image1.mod_date   as i1_mod_date
      ,image2.image_name as i2_image_name
      ,image2.comments   as i2_comments
      ,image2.status     as i2_status
      ,image2.mod_date   as i2_mod_date
  FROM (SELECT CASE WHEN status = 0 THEN 1 ELSE 0 END as rated
              ,patientid
              ,caseid
              ,image_name
              ,comments
              ,status
              ,mod_date
          FROM images
         WHERE image_name like '%{$group_name}%'
         ORDER BY 1 ASC, mod_date DESC
         LIMIT 1
       ) image1
  LEFT OUTER
  JOIN images image2
    ON image1.status > 0
   AND image2.patientid  = image1.patientid
   AND image2.caseid     = image1.caseid
   AND image2.status     = 0
   AND image2.mod_date   > image1.mod_date
   AND image2.image_name like '%{$group_name}%'
 ORDER BY image2.mod_date DESC
 LIMIT 1";

    $result_2 = mysql_query($sql_2,$connection);
    if($row = mysql_fetch_assoc($result_2)) {
        $imageGroup[$groupName]   = array();
        $imageGroup[$groupName][] = array(
            'image_name'  => $row['i1_image_name'],
            'comments'    => $row['i1_comments'], 
            'status'      => $row['i1_status'],
            'mod_date'    => $row['i1_mod_date']
            );
        if ( !empty( $row['i2_image_name'] ) ) {
            $imageGroup[$groupName][] = array(
                'image_name'  => $row['i2_image_name'],
                'comments'    => $row['i2_comments'], 
                'status'      => $row['i2_status'],
                'mod_date'    => $row['i2_mod_date']
            );
        }
    }

取代：

if (!isset($imageGroup[$groupName]) {   
    $imageGroup[$groupName] = array();

    $sql_2 = "SELECT * FROM images WHERE image_name like '%".$groupName."%'";
    $result_2 = mysql_query($sql_2,$connection);
    while($row - mysql_fetch_assoc($result_2)) {
        $imageGroup[$groupName][] = array( // sort each field as 
            'image_name' => $row['image_name'],
            'comments' => $row['comments'], 
            'status' => $row['status'], // determines whether image is rated or unrated
            'mod_date' => $row['mod_date'] // the date we need to compare
            );
    }
}
else {
    for ($i=0; $i <sizeof($imageGroup[$groupName]); $i++) {
        if ($imageGroup[$groupName][$i]['status'] == 0) {
        // compare??    

        }
        if ($imageGroup[$groupName][$i]['status'] !== 0) {
        // compare??    

        }


    }
}

完成后， $imageGroup[$groupName]將包含帶有一個或兩個元素的數組。

希望這是目標。 :)

Answer 2

這是您可以使用的一些舊代碼：

class ProductHelper {

// sort products by name
static function sort_name_asc($a,$b) {
    return strcmp($a['name'],$b['name']);
}
static function sort_name_desc($a,$b) {
    return strcmp($b['name'],$a['name']);
}
// sort products by price
static function sort_price_asc($a,$b) {
    return $a['price'] > $b['price'];
}
static function sort_price_desc($a,$b) {
    return $a['price'] < $b['price'];
}
// sort products by last update
static function sort_date_asc($a,$b) {
    return $a['created'] > $b['created'];
}
static function sort_date_desc($a,$b) {
    return $a['created'] < $b['created'];
}
// sort array by sort_order
static function sort_sort_order($a,$b) {
    return $a['sort_order'] > $b['sort_order'];
}

    function sortProducts($products, $sortMode) {
        if (!is_array($products)) return null;
        usort($products, 'ProductHelper::sort_'.$sortMode);
        return $products;
    }

}

使用示例：

$ProductHelper = new ProductHelper();
$ProductHelper->sortProducts($array_of_products, "date_desc");