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打印出std :: vector <std::wstring>

[英]Print out a std::vector<std::wstring>

我試圖使用std :: copy修改以打印出std::vector<std::wstring>的內容,但我不了解該代碼的工作方式是否足夠好,並且無法對其進行編譯。 代碼應該是什么?

我使用了Rob的示例,但它不起作用:

std::vector<std::wstring> keys = ...;
std::copy(keys.begin(), keys.end(), std::ostream_iterator<std::wstring>(std::wcout, " "));

我收到錯誤:

1>error C2665: 'std::ostream_iterator<_Ty>::ostream_iterator' : none of the 2 overloads could convert all the argument types
1>        with
1>        [
1>            _Ty=std::wstring
1>        ]
1>        C:\Program Files\Microsoft Visual Studio 8\VC\include\iterator(300): could be 'std::ostream_iterator<_Ty>::ostream_iterator(std::basic_ostream<_Elem,_Traits> &,const _Elem *)'
1>        with
1>        [
1>            _Ty=std::wstring,
1>            _Elem=char,
1>            _Traits=std::char_traits<char>
1>        ]
1>        while trying to match the argument list '(std::wostream, const char [2])'

當我使用wcout類型的wostream時,為什么告訴我_Elem=char

您必須使用wstring, wchar_t作為模板參數,並使用wcout作為輸出流:

std::copy(v.begin(), 
          v.end(), 
          std::ostream_iterator<std::wstring, wchar_t>(std::wcout, L"\n"));

測試程序:

#include <vector>
#include <string>
#include <iostream>
#include <iterator>

int main () {
  std::vector<std::wstring> v;
  v.push_back(L"Hello");
  v.push_back(L"World");
  std::copy(v.begin(),
            v.end(),
            std::ostream_iterator<std::wstring, wchar_t>(std::wcout, L"\n"));
}

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