選擇在一列中共享公共值但由其他值選擇的行

Question

我的示例表：

汽車選擇

| ID | CAR_ID |    DESCRIPTION |
|----|--------|----------------|
|  1 |      5 | tinted windows |
|  2 |      5 |  power windows |
|  3 |      6 |  power windows |
|  4 |      7 | tinted windows |

如何編寫一個sql語句，它接受輸入'tinted windows'和'power windows'並返回第1行和第2行（它們在car_id列中共享一個公共值）？

Answer 1

獲取與使用該輸入的所有行WHERE ，然后GROUP BY的car_id HAVING每個輸入的至少一排。 您可以使用下面的查詢來執行此操作。

SELECT car_id 
FROM CarOptions
WHERE (description = "tinted windows" OR 
       description = "power windows")
GROUP BY car_id
HAVING SUM(description = "tinted windows") > 0 AND 
       SUM(description = "power windows") > 0

見演示

要獲得整行，你可以做到，

SELECT *
FROM CarOptions
WHERE car_id IN (
  SELECT car_id
  FROM CarOptions
  WHERE (description = "tinted windows" OR
         description = "power windows")
  GROUP BY car_id
  HAVING SUM(description = "tinted windows") > 0 AND
         SUM(description = "power windows") > 0)

Answer 2

在這種特殊情況下你可以做到

SELECT * 
  FROM caroptions o JOIN
(
  SELECT car_id
    FROM caroptions
   WHERE description IN('tinted windows', 'power windows')
   GROUP BY car_id
  HAVING COUNT(DISTINCT description) = 2
) q  
    ON o.car_id = q.car_id

輸出：

| ID | CAR_ID |    DESCRIPTION |
|----|--------|----------------|
|  1 |      5 | tinted windows |
|  2 |      5 |  power windows |

這是SQLFiddle演示