[英]This is not permitted when the subquery follows =, !=, <, <= , >, >= or when the subquery is used as an expression
我在執行此查詢時遇到問題。 請在下面查看我的代碼。
SELECT (SELECT COUNT(FilteredAppointment.activitytypecodename) AS Expr1
FROM FilteredBusinessUnit INNER JOIN
FilteredSystemUser ON FilteredBusinessUnit.businessunitid = FilteredSystemUser.businessunitid INNER JOIN
FilteredAppointment ON FilteredSystemUser.systemuserid = FilteredAppointment.createdby
WHERE (FilteredBusinessUnit.name IN (@Branch))) AS Appointment,
(SELECT COUNT(FilteredLead.leadid) AS Expr1
FROM FilteredBusinessUnit AS FilteredBusinessUnit_7 INNER JOIN
FilteredSystemUser AS FilteredSystemUser_7 ON FilteredBusinessUnit_7.businessunitid = FilteredSystemUser_7.businessunitid INNER JOIN
FilteredLead ON FilteredSystemUser_7.systemuserid = FilteredLead.createdby
WHERE (FilteredBusinessUnit_7.name IN (@Branch)) AND (FilteredLead.new_referraltypename = 'Bank Staff')) AS Bank_Staff_Referral,
(SELECT COUNT(FilteredLead_3.leadid) AS Expr1
FROM FilteredBusinessUnit AS FilteredBusinessUnit_6 INNER JOIN
FilteredSystemUser AS FilteredSystemUser_6 ON FilteredBusinessUnit_6.businessunitid = FilteredSystemUser_6.businessunitid INNER JOIN
FilteredLead AS FilteredLead_3 ON FilteredSystemUser_6.systemuserid = FilteredLead_3.createdby
WHERE (FilteredBusinessUnit_6.name IN (@Branch)) AND (FilteredLead_3.new_referraltypename = 'Existing Customer')) AS Customer_Referral,
(SELECT COUNT(Filterednew_discoveryinterview.activityid) AS Expr1
FROM FilteredBusinessUnit AS FilteredBusinessUnit_5 INNER JOIN
FilteredSystemUser AS FilteredSystemUser_5 ON FilteredBusinessUnit_5.businessunitid = FilteredSystemUser_5.businessunitid INNER JOIN
Filterednew_discoveryinterview ON FilteredSystemUser_5.systemuserid = Filterednew_discoveryinterview.createdby
WHERE (FilteredBusinessUnit_5.name IN (@Branch))) AS Discovery_Interview,
(SELECT COUNT(FilteredLead_2.leadid) AS Expr1
FROM FilteredBusinessUnit AS FilteredBusinessUnit_4 INNER JOIN
FilteredSystemUser AS FilteredSystemUser_4 ON FilteredBusinessUnit_4.businessunitid = FilteredSystemUser_4.businessunitid INNER JOIN
FilteredLead AS FilteredLead_2 ON FilteredSystemUser_4.systemuserid = FilteredLead_2.createdby
WHERE (FilteredBusinessUnit_4.name IN (@Branch))) AS Generated_Leads,
（從FilteredBusinessUnit WHERE（FilteredBusinessUnit.name IN（@Branch））選擇名稱）AS分支
`
該代碼返回針對單個分支運行查詢的結果。 但是，將引發錯誤消息“子查詢返回了多個值。當子查詢遵循=，！=，<，<=，>，> =或將子查詢用作表達式時，不允許這樣做。”我選擇了多個分支。 我的猜測是，在運行select語句的最后一塊時會發生錯誤。
如何編寫此查詢以顯示多個分支的結果
請幫我
通過分別選擇@Branch變量。 這是更新的代碼示例
SELECT MQ.Name AS BranchName,
(SELECT COUNT(FilteredAppointment.activitytypecodename) AS Expr1
FROM FilteredBusinessUnit
INNER JOIN FilteredSystemUser ON FilteredBusinessUnit.businessunitid = FilteredSystemUser.businessunitid
INNER JOINFilteredAppointment ON FilteredSystemUser.systemuserid = FilteredAppointment.createdby
WHERE (FilteredBusinessUnit.name = MQ.Name)) AS Appointment,
(SELECT COUNT(FilteredLead.leadid) AS Expr1
FROM FilteredBusinessUnit AS FilteredBusinessUnit_7
INNER JOIN FilteredSystemUser AS FilteredSystemUser_7 ON FilteredBusinessUnit_7.businessunitid = FilteredSystemUser_7.businessunitid
INNER JOIN FilteredLead ON FilteredSystemUser_7.systemuserid = FilteredLead.createdby
WHERE (FilteredBusinessUnit_7.name = MQ.Name) AND (FilteredLead.new_referraltypename = 'Bank Staff')) AS Bank_Staff_Referral,
(SELECT COUNT(FilteredLead_3.leadid) AS Expr1
FROM FilteredBusinessUnit AS FilteredBusinessUnit_6 INNER JOIN
FilteredSystemUser AS FilteredSystemUser_6 ON FilteredBusinessUnit_6.businessunitid = FilteredSystemUser_6.businessunitid INNER JOIN
FilteredLead AS FilteredLead_3 ON FilteredSystemUser_6.systemuserid = FilteredLead_3.createdby
WHERE (FilteredBusinessUnit_6.name = MQ.Name) AND (FilteredLead_3.new_referraltypename = 'Existing Customer')) AS Customer_Referral,
(SELECT COUNT(Filterednew_discoveryinterview.activityid) AS Expr1
FROM FilteredBusinessUnit AS FilteredBusinessUnit_5 INNER JOIN
FilteredSystemUser AS FilteredSystemUser_5 ON FilteredBusinessUnit_5.businessunitid = FilteredSystemUser_5.businessunitid INNER JOIN
Filterednew_discoveryinterview ON FilteredSystemUser_5.systemuserid = Filterednew_discoveryinterview.createdby
WHERE (FilteredBusinessUnit_5.name = MQ.Name)) AS Discovery_Interview,
(SELECT COUNT(FilteredLead_2.leadid) AS Expr1
FROM FilteredBusinessUnit AS FilteredBusinessUnit_4 INNER JOIN
FilteredSystemUser AS FilteredSystemUser_4 ON FilteredBusinessUnit_4.businessunitid = FilteredSystemUser_4.businessunitid INNER JOIN
FilteredLead AS FilteredLead_2 ON FilteredSystemUser_4.systemuserid = FilteredLead_2.createdby
WHERE (FilteredBusinessUnit_4.name = MQ.Name)) AS Generated_Leads
FROM FilteredBusinessUnit MQ--I Assume this is where the Branch Name Is kept
WHERE MQ.Name In (@Branch)
當子查詢遵循=，！=，<，<=，>，> =或用作表達式時，不允許使用
[英]Not permitted when the subquery follows =, !=, <, <= , >, >= or when used as an expression
SQL錯誤：當子查詢遵循=，！=，<，<=，>，> =或將子查詢用作表達式時，不允許這樣做
[英]SQL ERROR: This is not permitted when the subquery follows =, !=, <, <= , >, >= or when the subquery is used as an expression
SQL錯誤-子查詢后跟=，！=，<，<=，>，> =或將子查詢用作表達式時，不允許這樣做
[英]Error in SQL - This is not permitted when the subquery follows =, !=, <, <= , >, >= or when the subquery is used as an expression
子查詢返回超過 1 個值。 當子查詢跟隨......或當子查詢用作表達式時，這是不允許的
[英]Subquery returned more than 1 value. This is not permitted when the subquery follows … or when the subquery is used as an expression
子查詢返回的值超過1。 當子查詢遵循> =或將子查詢用作表達式時，不允許這樣做
[英]Subquery returned more than 1 value. This is not permitted when the subquery follows>= or when the subquery is used as an expression
當子查詢遵循=，！=，<，<=，>，> =時，不允許這樣做
[英]This is not permitted when the subquery follows =, !=, <, <= , >, >=
sql server error =當子查詢跟隨=，！=，<，<=，>，> =或將子查詢用作表達式時，不允許這樣做
[英]sql server error = This is not permitted when the subquery follows =, !=, <, <= , >, >= or when the subquery is used as an expression
當子查詢遵循=，！=，<，<=，>，> =或將子查詢用作表達式時，不允許這樣做。 返回了多個值。
[英]This is not permitted when the subquery follows =, !=, <, <= , >, >= or when the subquery is used as an expression. More than 1 value was returned.
如何解決錯誤：“子查詢返回了多個值”。 當子查詢遵循=，！=，<，<=，>，> =或用作表達式時，不允許使用
[英]How to fix error: “Subquery returned more than 1 value”. Not permitted when subquery follows =, !=, <, <= , >, >= or used as an expression
子查詢返回的值超過1。 當子查詢遵循=，！=，<，<=，>，> =或用作表達式時，不允許使用
[英]Subquery returned more than 1 value. Not permitted when subquery follows =, !=, <, <= , >, >= or used as an expression
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