[英]MySQL: How to SELECT COUNT two field names from originating from field name on the same table
場景:我想創建一個查詢,該查詢可以返回來自同一列但標准不同的兩個或多個字段,以便我可以對數據進行計數。
SQL:
SELECT
FROM_UNIXTIME(news_date, '%Y-%m-%d') AS `DATE`,
COUNT(news_slant=1) AS `Neutral`,
COUNT(news_slant=2) AS `Positive`,
COUNT(news_slant=3) AS `Negative`
FROM tbl_news
GROUP BY `news_date`
ORDER BY `news_date`
通過使用case
內部count
:
SELECT
FROM_UNIXTIME(news_date, '%Y-%m-%d') AS `DATE`,
COUNT(case news_slant when 1 then 1 else null end) AS `Neutral`,
COUNT(case news_slant when 2 then 1 else null end) AS `Positive`,
COUNT(case news_slant when 3 then 1 else null end) AS `Negative`
FROM tbl_news
GROUP BY `news_date`
ORDER BY `news_date`
用例聲明:
SELECT FROM_UNIXTIME(news_date, '%Y-%m-%d') AS `DATE`,
COUNT(CASE WHEN news_slant=1 THEN 1 ELSE null END) AS Neutral,
COUNT(CASE WHEN news_slant=2 THEN 1 ELSE null END) AS Positive,
COUNT(CASE WHEN news_slant=3 THEN 1 ELSE null END) AS Negative ,
FROM MyTable
GROUP BY news_date
ORDER BY news_date
您可以使用標准IF
子句。 COUNT()
只計算非空值。
SELECT
FROM_UNIXTIME(news_date, '%Y-%m-%d') AS DATE,
COUNT(IF(news_slant=1,1,NULL)) AS Neutral,
COUNT(IF(news_slant=2,1,NULL)) AS Positive,
COUNT(IF(news_slant=3,1,NULL)) AS Negative
FROM tbl_news
GROUP BY news_date
ORDER BY news_date
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