我正在嘗試給我的掃描儀打電話，但它不起作用。 我該怎么辦？

Question

import java.util.Scanner;

public class Words
{
    public static void main (String[] args)
{
    Scanner myScan = new Scanner(System.in);
    String s1;
    int myAge;
    int time = 6;

    System.out.print("What is your name? ");
    s1 = myScan.nextLine();

    System.out.print("How old are you? ");
    myAge = myScan.nextInt(); 

    System.out.println("Really? Cause I am " + (myAge+3) + ". " + "Lets's meet up! ");
    s1 = myScan.nextLine();

    }
}

//最后一條命令執行完后，我將無法在終端窗口中輸入任何內容。 請幫忙。

Answer 1

在之間添加nextLine()

System.out.print("How old are you? ");
myAge = myScan.nextInt(); 

myScan.nextLine(); // add this

System.out.println("Really? Cause I am " + (myAge+3) + ". " + "Lets's meet up! ");
s1 = myScan.nextLine();

這是必需的，因為nextInt()僅消耗其讀取的int值，而不消耗其后的任何行尾字符。

nextLine()將使用\\r\\n （或行尾/定界符的任何結尾），而下一個標記將可供另一個nextLine() 。

Answer 2

在鍵入int之后鍵入回車。 nextline將以enter作為一行。 您需要在nextint之后添加一個額外的nextline調用，如下所示：

import java.util.Scanner;

public class Words
{
    public static void main (String[] args)
    {
        Scanner myScan = new Scanner(System.in);
        String s1;
        int myAge;
        int time = 6;

        System.out.print("What is your name? ");
        s1 = myScan.nextLine();

        System.out.print("How old are you? ");
        myAge = myScan.nextInt(); 
        s1 = myScan.nextLine();

        System.out.println("Really? Cause I am " + (myAge+3) + ". " + "Lets's meet up! ");
        s1 = myScan.nextLine();
    }
}