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[英]How to create correct JsonArray in Java using JSONObject using servlet
[英]How to create correct JSONArray in Java using JSONObject
我如何使用JSONObject在Java中創建如下所示的JSON對象?
{
"employees": [
{"firstName": "John", "lastName": "Doe"},
{"firstName": "Anna", "lastName": "Smith"},
{"firstName": "Peter", "lastName": "Jones"}
],
"manager": [
{"firstName": "John", "lastName": "Doe"},
{"firstName": "Anna", "lastName": "Smith"},
{"firstName": "Peter", "lastName": "Jones"}
]
}
我找到了很多示例,但沒有找到我確切的JSONArray字符串。
這是一些使用Java 6入門的代碼:
JSONObject jo = new JSONObject();
jo.put("firstName", "John");
jo.put("lastName", "Doe");
JSONArray ja = new JSONArray();
ja.put(jo);
JSONObject mainObj = new JSONObject();
mainObj.put("employees", ja);
編輯:由於這里有很多關於put
與add
的混淆,我將嘗試解釋它們之間的區別。 在Java 6中, org.json.JSONArray包含put
方法,在Java 7中, javax.json包含add
方法。
使用Java 7中的構建器模式的示例如下所示:
JsonObject jo = Json.createObjectBuilder()
.add("employees", Json.createArrayBuilder()
.add(Json.createObjectBuilder()
.add("firstName", "John")
.add("lastName", "Doe")))
.build();
我想您正在從服務器或文件中獲取此JSON,並且您想從中創建一個JSONArray對象。
String strJSON = ""; // your string goes here
JSONArray jArray = (JSONArray) new JSONTokener(strJSON).nextValue();
// once you get the array, you may check items like
JSONOBject jObject = jArray.getJSONObject(0);
希望這可以幫助 :)
可以編寫小的可重用方法來創建人員json對象,以避免重復代碼
JSONObject getPerson(String firstName, String lastName){
JSONObject person = new JSONObject();
person .put("firstName", firstName);
person .put("lastName", lastName);
return person ;
}
public JSONObject getJsonResponse(){
JSONArray employees = new JSONArray();
employees.put(getPerson("John","Doe"));
employees.put(getPerson("Anna","Smith"));
employees.put(getPerson("Peter","Jones"));
JSONArray managers = new JSONArray();
managers.put(getPerson("John","Doe"));
managers.put(getPerson("Anna","Smith"));
managers.put(getPerson("Peter","Jones"));
JSONObject response= new JSONObject();
response.put("employees", employees );
response.put("manager", managers );
return response;
}
請嘗試這個...希望對您有所幫助
JSONObject jsonObj1=null;
JSONObject jsonObj2=null;
JSONArray array=new JSONArray();
JSONArray array2=new JSONArray();
jsonObj1=new JSONObject();
jsonObj2=new JSONObject();
array.put(new JSONObject().put("firstName", "John").put("lastName","Doe"))
.put(new JSONObject().put("firstName", "Anna").put("v", "Smith"))
.put(new JSONObject().put("firstName", "Peter").put("v", "Jones"));
array2.put(new JSONObject().put("firstName", "John").put("lastName","Doe"))
.put(new JSONObject().put("firstName", "Anna").put("v", "Smith"))
.put(new JSONObject().put("firstName", "Peter").put("v", "Jones"));
jsonObj1.put("employees", array);
jsonObj1.put("manager", array2);
Response response = null;
response = Response.status(Status.OK).entity(jsonObj1.toString()).build();
return response;
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