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[英]Im trying to delete a mysql file using php here is the code once delete is pressed nothing happens any ideas?
[英]Any ideas for a php code for this?
我需要做一些數學計算,而我似乎找不到辦法。
我有以下表,由此查詢產生:
SELECT materii.id,
materii.materie,
GROUP_CONCAT(note.note) AS note,
GROUP_CONCAT(DISTINCT teza.`teza`) AS teza
FROM materii
LEFT JOIN teza ON materii.id = teza.id_materie
LEFT JOIN note ON materii.id = note.id_materie
LEFT JOIN elevi ON note.id_elev = elevi.cod_elev
LEFT JOIN luni ON note.`luna_nota`=luni.`id`
WHERE elevi.`cod_elev` = 1 AND luna_nota = 9
GROUP BY materii.id, materii.materie
ORDER BY materii.materie
我需要做類似的事情:
$notele = mysql_query($pentrumedie)
or die("Nu am gasit note in baza de date");
$numar_note = mysql_num_rows($notele);
if($numar_note==0)
{
}
else
{
while($rand2=mysql_fetch_array($notele))
{
$note1 = ($rand2['notele'] / $numar_note);
$medie_septembrie = ($note1 / $cate_note_sunt);
}
}
我需要為所有“注釋”做類似的事情,但是$ rand2 ['notele']需要是它們的總和,如果有更多“注意”,並且如果有“teza”的值,那么數學公式需要是:
(($rand2['notele'] / $numar_note) * 3 + teza) / 4
我嘗試了一些功能,但沒有一個工作....任何想法? 謝謝!!!
你可以嘗試改變你的sql語句
SELECT materii.id,
materii.materie,
SUM(note.note)/COUNT(note.note) AS medie,
GROUP_CONCAT(DISTINCT teza.`teza`) AS teza
FROM materii
LEFT JOIN teza ON materii.id = teza.id_materie
LEFT JOIN note ON materii.id = note.id_materie
LEFT JOIN elevi ON note.id_elev = elevi.cod_elev
LEFT JOIN luni ON note.`luna_nota`=luni.`id`
WHERE elevi.`cod_elev` = 1 AND luna_nota = 9
GROUP BY materii.id, materii.materie
ORDER BY materii.materie
在PHP中使用類似的東西
$medii = array();
while($rand = mysql_fetch_assoc($notele))
{
if($rand["teza"] == "" || $rand["teza"] == NULL)
{
$medii[] = array("materie" => $rand["materie"],
"medie" => $rand["medie"]);
}
else
{
$medii[] = array("materie" => $rand["materie"],
"medie" => ((float)$rand["medie"]*3 + (float)$rand["teza"])/4);
}
}
var_dump($medii);
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