MySQL選擇范圍之間的最后x天

Question

此查詢返回從今天到90天之前的所有選定值：

 SELECT max(cases_visits.created_dt), users_profiles.account_num,
    concat(cases.patient_first_initial,
    cases.patient_middle_initial, cases.patient_last_initial) AS initials,
    concat(users.first_name, ' ',users.last_name) as name   
    FROM cases
    JOIN users_profiles
    ON users_profiles.user_id=cases.doctor_id
    JOIN cases_visits
    ON cases.id=cases_visits.case_id

    join users on users.id = cases.doctor_id

    WHERE cases_visits.patient_visit_type = 'NP' && cases_visits.created_dt BETWEEN     curdate() - INTERVAL 90 DAY AND SYSDATE()

    group by users.first_name

我想找到一個查詢，該查詢現在將選擇完全相同的內容，但前提是前一個查詢中不存在記錄。 示例：返回> 90天前的記錄，而這些記錄在過去90天內沒有記錄。

我已嘗試執行此操作：（請注意，查詢中的2013-07-03是我第一次運行后的90天）

    SELECT cases_visits.created_dt, users_profiles.account_num,
    concat(cases.patient_first_initial,
    cases.patient_middle_initial, cases.patient_last_initial) AS initials,
    concat(users.first_name, ' ',users.last_name) as name
    FROM cases
    JOIN users_profiles
    ON users_profiles.user_id=cases.doctor_id
   JOIN cases_visits
   ON cases.id=cases_visits.case_id
   join users on users.id = cases.doctor_id
   WHERE cases_visits.created_dt < '2013-07-03'
   group by users.first_name

我認為這不能提供適當的數據，因為我需要以某種方式排除過去90天內存在的記錄。

這就是我想做的：選擇過去90天內aa值=到'NP'的記錄，然后我需要選擇90天內沒有np值的記錄，但是這些記錄應該完全從第一個查詢開始就是唯一的（即個人可以在90天內和180天內收到一個案件，我不需要他的記錄。）

編輯：我忘了提起我已經嘗試過此查詢與附近的錯誤中：

SELECT cases_visits.created_dt, users_profiles.account_num,
concat(cases.patient_first_initial,
cases.patient_middle_initial, cases.patient_last_initial) AS initials,
concat(users.first_name, ' ',users.last_name) as name    
FROM cases 
JOIN users_profiles
ON users_profiles.user_id=cases.doctor_id    
JOIN cases_visits
ON cases.id=cases_visits.case_id    
join users on users.id = cases.doctor_id    
WHERE cases_visits.created_dt < '2013-07-03'
and cases_visits.patient_visit_type = 'NP'    
and not in (select created_dt from cases_visits where  cases_visits.patient_visit_type = 'NP' && cases_visits.created_dt BETWEEN curdate() - INTERVAL 90 DAY AND SYSDATE())   
group by users.first_name

Answer 1

您可以使用子查詢：

select * from table where ID NOT IN (select id from table where a=1);

本質上，這將從表中選擇與內部查詢匹配的記錄不匹配的記錄。

Answer 2

SELECT * FROM table WHERE cases_visits.created_dt < '2013-07-03'
AND case_visist.SOME_UNIQUE_ID NOT IN 
(SELECT case_visist.SOME_UNIQUE_ID FROM table WHERE cases_visits.patient_visit_type = 'NP' && cases_visits.created_dt BETWEEN     curdate() - INTERVAL 90 DAY AND SYSDATE() )

您可以使用NOT IN語句並輸入SELECT語句，以選擇應排除的所有記錄。 此線程中的更多信息

Answer 3

這組應該是同一位醫生，相同病例但不同的訪視？

SELECT max(cases_visits.created_dt), users_profiles.account_num,
  concat(cases.patient_first_initial,
  cases.patient_middle_initial, cases.patient_last_initial) AS initials,
  concat(users.first_name, ' ',users.last_name) as name   
FROM cases
JOIN users_profiles
  ON users_profiles.user_id=cases.doctor_id
JOIN cases_visits
  ON cases.id=cases_visits.case_id
JOIN users
  ON users.id = cases.doctor_id
WHERE cases_visits.patient_visit_type = 'NP' && cases_visits.created_dt <= curdate() - INTERVAL 90 DAY
  AND EXISTS(SELECT *
         FROM case_visits AS inside
         WHERE inside.case_id = cases.id
           AND inside.patient_visit_type = 'NP'
           AND inside.created_dt BETWEEN curdate() - INTERVAL 90 DAY AND SYSDATE())
GROUP BY account_num, initials, name