[英]Java my loan class formula is returning infinity
我的代碼運行得很好,除了我每月貸款計算器的返回值。 它會繼續為我的每月付款和總付款返回Infinity。 請幫助公式。 這是一項作業。 我需要知道的是我是否錯誤地實現了公式。 我感覺到它試圖以某種方式除以0然后返回無窮大,但是我可能是錯的。
public class MyLoan
{
private double amountBorrowed;
private double yearlyRate;
private int years;
public double A;
public double n = years * 12;
public MyLoan(double amt, double rt, int yrs)
{
amountBorrowed = amt;
yearlyRate = rt;
years = yrs;
}
public double getAmountBorrowed()
{
return amountBorrowed;
}
public double getYearlyRate()
{
return yearlyRate;
}
public int getYears()
{
return years;
}
public double monthlyPayment()
{
double i = (yearlyRate / 100) / 12;
A = (amountBorrowed) * (i * Math.pow(1+i, n)) / (Math.pow(1+i, n) -1);
return A;
}
public double totalPayment()
{
return A * (years * 12);
}
public String toString()
{
return "Loan: " + "$" + amountBorrowed + " at " + yearlyRate + " for " + years + " years";
}
public static void main(String[] args)
{
final double RATE15 = 5.75;
final double RATE30 = 6.25;
StdOut.println("***** Welcome to the Loan analyzer! *****");
String ans = "Y";
do {
StdOut.print("\n Enter the principle amount to borrow: ");
double amount = StdIn.readDouble();
MyLoan fifteenYears = new MyLoan(amount, RATE15, 15);
MyLoan thirtyYears = new MyLoan(amount, RATE30, 30);
double amount15 = fifteenYears.monthlyPayment();
double total15 = fifteenYears.totalPayment();
double amount30 = thirtyYears.monthlyPayment();
double total30 = thirtyYears.totalPayment();
StdOut.println("===========ANALYSES==========");
StdOut.println(fifteenYears);
StdOut.println("Monthly payment = " + "$" + amount15);
StdOut.println("Total payment = " + "$" + total15);
StdOut.println("");
StdOut.println("");
StdOut.println(thirtyYears);
StdOut.println("Monthly payment = " + "$" + amount30);
StdOut.println("Total payment = " + "$" + total30);
StdOut.println("=============================");
StdOut.print("\n ** Do you want to continue (y/n)? ");
ans = StdIn.readString();
} while (ans.toUpperCase().equals("Y"));
StdOut.println("\n********** Thank you. Come again! **********");
}
}
有很多計算興趣的方法,最常見的是
A = amountBorrowed * (yearlyRate / 100) / 12;
您應該自己進行調試,但是我會給您一個提示。 1 ^ n是什么(n是一個正整數)? 您在代碼中的哪里使用此構造?
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