可比接口問題

Question

嗨，我為Comparable接口編寫了簡單的代碼，如下所示

import java.util.*;
class Gaurav123 implements Comparable<Gaurav123>
{
  String title;
  Gaurav123()
  {

  }

  Gaurav123(String title)
  {
    this.title=title;
  }

  public int compareTO(Gaurav123 b)
  {
    return title.compareTo(b.title);
  }
}

public class Gaurav1234
{

  public static void main(String [] args)
  {
    Gaurav123 g1=new Gaurav123("gaurav");
    Gaurav123 g2=new Gaurav123("Surbhi");
    Gaurav123 g3=new Gaurav123("Kailash");
    TreeSet<Gaurav123>ts=new TreeSet<Gaurav123>();
    ts.add(g1);
    ts.add(g2);
    ts.add(g3);
  }
}

但是我收到這個錯誤

C:\Users\gakaushik\Desktop>javac Gaurav1234.java
Gaurav1234.java:2: Gaurav123 is not abstract and does not override abstract meth
od compareTo(Gaurav123) in java.lang.Comparable
class Gaurav123 implements Comparable<Gaurav123>
^
1 error

任何想法是什么問題。 我遵循所有可比接口協議

Answer 1

Java完全區分大小寫...您的方法稱為

compareTO

應該叫

compareTo

但是，下次一定要仔細閱讀錯誤消息，這通常是個很好的提示。...問一個問題之前要做的另一件事是將錯誤復制並粘貼到您找到的任何搜索引擎中（甚至在Stackoverflow）