Java索引超出范圍錯誤

Question

我將Java代碼編寫為Minecraft服務器的插件，但是邏輯原理本質上是通用的。

public void doReviewMember(CommandSender playerSent) {
    if (!reviewsMember.isEmpty()) {
        Review doThis = null;

        ArrayList<Review> players = new ArrayList<Review>();
        ArrayList<Review> playersVIP = new ArrayList<Review>();
        ArrayList<Review> playersVIPplus = new ArrayList<Review>();

        for (int c1 = 0; c1 < reviewsMember.size(); c1++) {
            if  (Bukkit.getPlayer(reviewsMember.get(c1).getName()).hasPermission("reviewplugin.vipplus"))
                playersVIPplus.add(reviewsMember.get(c1));
            else if (Bukkit.getPlayer(reviewsMember.get(c1).getName()).hasPermission("reviewplugin.vip"))
                playersVIP.add(reviewsMember.get(c1));
            else players.add(reviewsMember.get(c1));
        }

        if (playersVIPplus.size() > 0)
            doThis = playersVIPplus.get(0);
        else if (playersVIP.size() > 0)
            doThis = playersVIP.get(0);
        else doThis = players.get(0);

        Bukkit.getPlayer(playerSent.getName()).sendMessage("§4[§6ReviewPlugin§4] §eThis review is for §b" + doThis.getName());
        Bukkit.getPlayer(playerSent.getName()).teleport(doThis.getLocation());
        reviewsMember.remove(doThis);
        if (reviewsMember.size() > 1)
            Bukkit.getPlayer(playerSent.getName()).sendMessage("§4[§6ReviewPlugin§4] §eThere are " + reviewsMember.size() + " member reviews left to do.");
        else if (reviewsMember.size() == 1)
            Bukkit.getPlayer(playerSent.getName()).sendMessage("§4[§6ReviewPlugin§4] §eThere is " + reviewsMember.size() + " member review left to do.");
        else
            Bukkit.getPlayer(playerSent.getName()).sendMessage("§4[§6ReviewPlugin§4] §eThere are no more Member reviews to do at this time!");
    }
    else {
        Bukkit.getPlayer(playerSent.getName()).sendMessage("§4[§6ReviewPlugin§4] §eThere are no more Member reviews to do at this time!");
    }
}

索引超出范圍錯誤發生在for循環中，所以我不知道我要去哪里。 這已在Windows 8計算機上經過了無錯誤測試，但是在Linux中實施時，每次都失敗，並出現索引越界錯誤。

Answer 1

除非某些后台線程在循環中間修改數組， 否則以上代碼不會失敗。 這很可能是您遇到問題的原因。