[英]SQL Return different values on the same row, based on a value thats in the same table
我在嘗試獲取我的結果以顯示他們需要它們來顯示時遇到了非常困難的時間...這里和我的查詢看起來像的示例,下面將是我需要的結果...
iv一直在嘗試案例陳述和加入,但沒有運氣,如果有人可以幫助的話,我將非常感激。
table name dbo.DTLPAYMENTS
columns
PTNO
CD
AMT
DESCRIPTION
我的查詢像這樣向我顯示結果...也永遠不會有相等數量的貸方和借方行。 因此,一個人的借方(> 0)多於貸方(<0),反之亦然。...
PTNO / CD / AMT / DESCRIPTION
10007558931 30073 688.82 PAYMENT-ME
10007558931 30073 -704.44 PAYMENT-ME
10007558931 30073 704.44 PAYMENT-ME
10007558931 30073 -688.82 PAYMENT-ME
10007558931 30073 -698.82 PAYMENT-ME
我需要在單獨的列中使用借方和貸方
如果有任何可能的話,我可以像這樣...
PTNO / CD / AMT / DESCRIPTION / CD / AMT / DESCRIPTION
10007558931 30073 688.82 PAYMENT-ME 30073 -688.82 PAYMENT-ME
10007558931 30073 704.44 PAYMENT-ME 30073 -698.82 PAYMENT-ME
10007558931 30073 -704.44 PAYMENT-ME
如果有人能幫助我,謝謝你
首先,使用CTE將貸方和借方分離為單獨的數據集,然后根據PTNO,CD和AMT的反值(* -1)進行完全聯接。
編輯:由於基於AMT的加入不是目標,因此我使用BatchSeqID作為按時間順序對數據進行排序的方法。 然后使用ROW_NUMBER()對兩個數據集進行排序,然后在該值上加入。
;WITH
Credit AS
( SELECT PTNO,CD,AMT,DESCRIPTION,
ROW_NUMBER()OVER(PARTITION BY PTNO,CD ORDER BY BatchSeqID) AS Sort
FROM dbo.DTLPAYMENTS
WHERE AMT < 0 ),
Debit AS
( SELECT PTNO,CD,AMT,DESCRIPTION,
ROW_NUMBER()OVER(PARTITION BY PTNO,CD ORDER BY BatchSeqID) AS Sort
FROM dbo.DTLPAYMENTS
WHERE AMT > 0 )
SELECT ISNULL(c.PTNO,d.PTNO) AS PTNO,
ISNULL(c.CD,d.CD) AS CD,
--Credit data
c.AMT AS CRAMT,
c.DESCRIPTION AS CRDESCRIPTION,
--Debit data
d.AMT AS DBTAMT,
d.DESCRIPTION AS DBTDESCRIPTION
FROM Credit c
FULL JOIN Debit d
ON d.PTNO = c.PTNO
AND d.CD = c.CD
AND d.Sort= c.Sort
如果您不喜歡Matt的解決方案以及行重復的風險,則可以將每個事務放在不同的行上:
SELECT PTNO,
CASE WHEN AMT < 0 THEN cd ELSE null END DBTCD,
CASE WHEN AMT < 0 THEN amt ELSE null END AMTCD,
CASE WHEN AMT < 0 THEN DESCRIPTION ELSE null END DBTDESCRIPTION,
CASE WHEN AMT > 0 THEN cd ELSE null END CRCD,
CASE WHEN AMT > 0 THEN amt ELSE null END CRAMT,
CASE WHEN AMT > 0 THEN DESCRIPTION ELSE null END CRDESCRIPTION
FROM TABLE1
order by PTNO, AMT
在這里,您可以查看和播放結果。
PTNO DBTCD AMTCD DBTDESCRIPTION CRCD CRAMT CRDESCRIPTION
10007558931 30073 -704 PAYMENT-ME (null) (null) (null)
10007558931 30073 -699 PAYMENT-ME (null) (null) (null)
10007558931 30073 -689 PAYMENT-ME (null) (null) (null)
10007558931 (null) (null) (null) 30073 689 PAYMENT-ME
10007558931 (null) (null) (null) 30073 704 PAYMENT-ME
假設您要根據amt
列的大小對輸出進行排序,請嘗試:
select ptno,
max(case sign(amt) when 1 then cd end) dr_cd,
max(case sign(amt) when 1 then amt end) dr_amt,
max(case sign(amt) when 1 then description end) dr_desc,
max(case sign(amt) when -1 then cd end) cr_cd,
max(case sign(amt) when -1 then amt end) cr_amt,
max(case sign(amt) when -1 then description end) cr_desc
from (select d.*,
row_number() over (partition by ptno, cd, sign(amt)
order by abs(amt)) rn
from DTLPAYMENTS d) sq
group by ptno, cd, rn
order by ptno, cd, rn
SQLFiddle 在這里 。
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