[英]calling a php function in javascript
我不知道如何在我的問題中使用ajax:我在php(賦值)中有一個函數可以更新數據庫中的臨時表,我想當用戶單擊按鈕(javascript中定義的反饋函數)時使用此函數(分配)運行,我該怎么辦?
<script>
function feedback(){
var boxes = document.getElementsByClassName('box');
for(var j = 0; j < boxes.length; j++){
if(boxes[j].checked) {
assign(1);
}
else{
assign(0);
}
}
}
</script>
<?php
$con = mysql_connect("localhost", "root", "")
or die(mysql_error());
if (!$con) {
die('Could not connect to MySQL: ' . mysql_error());
}
mysql_select_db("project", $con)
or die(mysql_error());
$result = mysql_query("select * from words");
echo "<table border='1'>
<tr>
<th>word</th>
<th>meaning</th>
<th>checking</th>
</tr>";
while($row = mysql_fetch_array($result)) {
echo "<tr>";
echo "<td>" . $row['word'] . "</td>";
$idd= $row['id'] ;
echo "<td>". "<div class='hiding' style='display:none'>".$row['meaning']."</div>"."</td>";
echo "<td>";
echo "<input class=\"box\" name=\"$idd\" type=\"checkbox\" value=\"\"> ";
echo "</td>";
echo "</tr>";
}
echo "</table>";
function assign($checkparm){
//mysql_query("update words set checking=$checkparm ");
mysql_query("create TEMPORARY TABLE words1user1 as (SELECT * FROM words) ");
mysql_query("update words1user1 set checking=$checkparm ");
}
mysql_close($con);
?>
<button onclick="ShowMeanings()">ShowMeanings</button>
<button onclick="feedback()">sendfeedback</button>
頁面加載后,只有一種方法可以調用php函數:
1.ajax:
function callPHP() {
$.ajax ({
url: "yourPageName.php",
data: { action : assign }, //optional
success: function( result ) {
//do something after you receive the result
}
}
在您的PHP中,編寫
if ($_POST["action"] == "assign")
{
assign(your parameters); //You need to put the parameters you want to pass in
//the data field of the ajax call, and use $_POST[]
//to get them
}
互聯網上有很多很棒的指南。 但是,我建議您也了解JQuery 。 這將對您的學習曲線有所幫助。
function ajaxCall(){
$.ajax({
type: "GET",
url: "scripts/on/serverside.php"
});
};
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