如何在正則表達式中使用\\ n？

Question

初始字符串為

System.out.println(myString)

看起來像這樣

Name: Sacha
Last name: Sidor
.............
Name: Masha
........

---

我試圖捕捉第二個名字，即瑪莎

            Pattern pattern = Pattern.compile("(?:Name:.*?){2}\\n");
            Matcher matcher = pattern.matcher(myString);
            String secondName = "";
            while (matcher.find()) {
            secondName = matcher.group();
              }
            System.out.println(secondName); // prints nothing ???

Answer 1

使用Pattern.DOTALL標志進行. 匹配所有字符，包括換行符。 沒有DOTALL標志， . 與換行符不匹配。

Pattern pattern = Pattern.compile("(?:Name:.*?)(?:Name: )([^\\n]+)", Pattern.DOTALL);
Matcher matcher = pattern.matcher(myString);
String secondName = "";
if (matcher.find())
    secondName = matcher.group(1);
System.out.println(secondName);