[英]Creating a view, Error Code: 1052. Column “id” in field is ambiguous
[英]Error Code: 1052 Column 'admin_id' in field list is ambiguous
您好我已經嘗試在我的數據庫中創建時間表視圖但我遇到了admin_id列的問題。 我正在重復使用其他任務的代碼,因此我很困惑,為什么它不起作用。 請幫我!!!
選擇聲明
SELECT timesheet_id, class, day, hour, week, admin_id, date_added FROM timesheet, day, classes, admin
WHERE timesheet_id AND
classes.class_id = timesheet.class_id AND
day.day_id = timesheet.day_id AND
admin.admin_id = timesheet.admin_id ORDER BY timesheet.timesheet_id.;
數據庫代碼
'CREATE DATABASE /*!32312 IF NOT EXISTS*/`timesheet` /*!40100 DEFAULT CHARACTER SET latin1 */;
USE `timesheet`;
/*Table structure for table `admin` */
DROP TABLE IF EXISTS `admin`;
CREATE TABLE `admin` (
`admin_id` int(100) NOT NULL AUTO_INCREMENT,
`username` varchar(10) DEFAULT NULL,
`password` char(30) DEFAULT NULL,
PRIMARY KEY (`admin_id`)
) ENGINE=InnoDB AUTO_INCREMENT=3 DEFAULT CHARSET=latin1;
/*Data for the table `admin` */
insert into `admin`(`admin_id`,`username`,`password`) values (1,'1627724','troll1'),(2,'1627406','troll2');
/*Table structure for table `classes` */
DROP TABLE IF EXISTS `classes`;
CREATE TABLE `classes` (
`class_id` int(11) NOT NULL AUTO_INCREMENT,
`class` varchar(30) DEFAULT NULL,
PRIMARY KEY (`class_id`)
) ENGINE=InnoDB AUTO_INCREMENT=9 DEFAULT CHARSET=latin1;
/*Data for the table `classes` */
insert into `classes`(`class_id`,`class`) values (1,'Validate and Test'),(2,'Complex Web'),(3,'Advanced OO Web'),(4,'Project Management'),(5,'Project Web'),(6,'Meeting'),(7,'Study'),(8,'Software Development');
/*Table structure for table `day` */
DROP TABLE IF EXISTS `day`;
CREATE TABLE `day` (
`day_id` int(11) NOT NULL AUTO_INCREMENT,
`day` varchar(15) NOT NULL,
PRIMARY KEY (`day_id`)
) ENGINE=InnoDB AUTO_INCREMENT=8 DEFAULT CHARSET=latin1;
/*Data for the table `day` */
insert into `day`(`day_id`,`day`) values (1,'Monday'),(2,'Tuesday'),(3,'Wednesday'),(4,'Thursday'),(5,'Friday'),(6,'Saturday'),(7,'Sunday');
/*Table structure for table `menu` */
DROP TABLE IF EXISTS `menu`;
CREATE TABLE `menu` (
`Menu_id` int(100) NOT NULL AUTO_INCREMENT,
`Menu` char(10) DEFAULT NULL,
PRIMARY KEY (`Menu_id`)
) ENGINE=InnoDB AUTO_INCREMENT=5 DEFAULT CHARSET=latin1;
/*Data for the table `menu` */
insert into `menu`(`Menu_id`,`Menu`) values (1,'index'),(2,'contact us'),(3,'project'),(4,'timesheets');
/*Table structure for table `timesheet` */
DROP TABLE IF EXISTS `timesheet`;
CREATE TABLE `timesheet` (
`timesheet_id` int(11) NOT NULL AUTO_INCREMENT,
`class_id` int(11) NOT NULL,
`day_id` int(11) NOT NULL,
`hour` float DEFAULT NULL,
`week` varchar(8) NOT NULL,
`admin_id` int(11) NOT NULL,
`date_added` date NOT NULL,
PRIMARY KEY (`timesheet_id`),
KEY `class_fk` (`class_id`),
KEY `day_fk` (`day_id`),
KEY `admin_fk` (`admin_id`),
CONSTRAINT `admin_fk` FOREIGN KEY (`admin_id`) REFERENCES `admin` (`admin_id`),
CONSTRAINT `class_fk` FOREIGN KEY (`class_id`) REFERENCES `classes` (`class_id`),
CONSTRAINT `day_fk` FOREIGN KEY (`day_id`) REFERENCES `day` (`day_id`)
) ENGINE=InnoDB AUTO_INCREMENT=6 DEFAULT CHARSET=latin1;
/*Data for the table `timesheet`'
insert into `timesheet`(`timesheet_id`,`class_id`,`day_id`,`hour`,`week`,`admin_id`,`date_added`) values (1,1,1,1,'week1',2,'2013-10-14'),(2,2,5,6,'week1',2,'2013-10-14'),(3,1,3,5,'week1',2,'2013-10-14'),(4,5,6,2,'week1',2,'2013-10-14'),(5,8,6,4,'week1',2,'2013-10-14');
這意味着在查詢中訪問的表中有多個名為admin_id的列,因此mysql不知道從哪個列返回結果。
更改select語句以包括表別名(admin或timesheet),如下所示: SELECT timesheet_id, class, day, hour, week, timesheet.admin_id, date_added FROM timesheet
由於admin_id
存在於2個表( admin
和timesheet
)中,因此無法在沒有表名或別名的 SELECT
列表中使用它。
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