[英]how to remove action and controller from url in rails link_to
這是我的link_to
<%= link_to sub_category.name, controller: :posts, action: :product, id: "#{sub_category.slug}-#{sub_category.id}" %>
哪個指向URL
http://localhost:3000/posts/product/fifith-category-s-sub-category-2
我需要如下網址
http://localhost:3000/fifith-category-s-sub-category-2
我該怎么做。
我的route.rb
resources :posts
match ':controller(/:action(/:id))(.:format)', via: [:get,:post]
如果您希望路徑/:id
與您的posts#product
匹配,則您的路線中應包含以下內容:
resources :posts
match ':id', to: 'posts#product`, via: :get
match ':controller(/:action(/:id))(.:format)', via: [:get, :post]
@MarekLipka的建議是正確的,但是像這樣定義您的路由將占用您應用程序中的所有單級名稱空間,即,“ / anything”將默認路由到posts#product
。
我建議使用某種形式的標識符來確定應該去posts#product
路線。 對您有用的取決於您為什么要這樣做。 幾個選項是:
使用簡短的名稱空間:
scope '/pp' do
get ':id', to: 'posts#product
end
# "/pp/:id" routes to 'posts/product'
# pp is a random short name I picked, it could be anything
# link
<%= link_to sub_category.name, "pp/#{sub_category.slug}-#{sub_category.id}" %>
使用約束:
get ':id', to: 'posts#product`, constraints: { :id => /sub\-category/ }
# only id's with 'sub-cateogry' route to 'posts/product'
# link (assuming that sub_category.slug has 'sub-category' words in it)
<%= link_to sub_category.name, "#{sub_category.slug}-#{sub_category.id}" %>
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