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[英]hibernate “IllegalArgumentException occurred calling getter”
[英]Hibernate - IllegalArgumentException occurred calling getter of model
我的hibernate模型出現了這個錯誤,我無法弄清楚是什么問題。
Tag.java:
@Entity
@Table(name = "tag")
public class Tag implements java.io.Serializable {
private Integer idTag;
private String name;
private Set<Question> questions = new HashSet<Question>(0);
@Id
@GeneratedValue(strategy = IDENTITY)
@Column(name = "idtag", unique = true, nullable = false)
public Integer getIdTag() {
return this.idTag;
}
public void setIdTag(Integer idtag) {
this.idTag = idtag;
}
[...]
@OneToMany(fetch = FetchType.LAZY, mappedBy = "tag")
public Set<Question> getQuestions() {
return this.questions;
}
public void setQuestions(Set<Question> questions) {
this.questions = questions;
}
}
Question.java:
@Entity
@Table(name = "question")
@Inheritance(strategy=InheritanceType.JOINED)
public class Question implements java.io.Serializable {
protected Integer idQuestion;
protected Tag tag;
@Id
@GeneratedValue(strategy = IDENTITY)
@Column(name = "idquestion", unique = true, nullable = false)
public Integer getIdQuestion() {
return this.idQuestion;
}
public void setIdQuestion(Integer idquestion) {
this.idQuestion = idquestion;
}
@ManyToOne(fetch = FetchType.LAZY)
@JoinColumn(name = "idtag")
public Tag getTag() {
return this.tag;
}
public void setTag(Tag tag) {
this.tag = tag;
}
[...]
}
QuestionText.java:
@Entity
@Table(name = "question_text")
@PrimaryKeyJoinColumn(name="idquestion")
public class QuestionText extends Question implements java.io.Serializable {
[...]
}
這是出現此錯誤時(在query.list()
):
q = "FROM QuestionText WHERE tag = :tag";
query = (Query) session.createQuery(q);
query.setParameter("tag", tag);
List<Question> data = query.list();
堆棧跟蹤:
org.hibernate.PropertyAccessException: IllegalArgumentException occurred calling getter of model.Tag.idtag
org.hibernate.property.BasicPropertyAccessor$BasicGetter.get(BasicPropertyAccessor.java:187)
org.hibernate.tuple.entity.AbstractEntityTuplizer.getIdentifier(AbstractEntityTuplizer.java:344)
org.hibernate.persister.entity.AbstractEntityPersister.getIdentifier(AbstractEntityPersister.java:4537)
org.hibernate.persister.entity.AbstractEntityPersister.isTransient(AbstractEntityPersister.java:4259)
org.hibernate.engine.internal.ForeignKeys.isTransient(ForeignKeys.java:209)
org.hibernate.engine.internal.ForeignKeys.getEntityIdentifierIfNotUnsaved(ForeignKeys.java:248)
org.hibernate.type.EntityType.getIdentifier(EntityType.java:510)
org.hibernate.type.ManyToOneType.nullSafeSet(ManyToOneType.java:174)
org.hibernate.param.NamedParameterSpecification.bind(NamedParameterSpecification.java:66)
org.hibernate.loader.hql.QueryLoader.bindParameterValues(QueryLoader.java:612)
org.hibernate.loader.Loader.prepareQueryStatement(Loader.java:1875)
org.hibernate.loader.Loader.executeQueryStatement(Loader.java:1836)
org.hibernate.loader.Loader.executeQueryStatement(Loader.java:1816)
org.hibernate.loader.Loader.doQuery(Loader.java:900)
org.hibernate.loader.Loader.doQueryAndInitializeNonLazyCollections(Loader.java:342)
org.hibernate.loader.Loader.doList(Loader.java:2526)
org.hibernate.loader.Loader.doList(Loader.java:2512)
org.hibernate.loader.Loader.listIgnoreQueryCache(Loader.java:2342)
org.hibernate.loader.Loader.list(Loader.java:2337)
org.hibernate.loader.hql.QueryLoader.list(QueryLoader.java:495)
org.hibernate.hql.internal.ast.QueryTranslatorImpl.list(QueryTranslatorImpl.java:357)
org.hibernate.engine.query.spi.HQLQueryPlan.performList(HQLQueryPlan.java:195)
org.hibernate.internal.SessionImpl.list(SessionImpl.java:1269)
org.hibernate.internal.QueryImpl.list(QueryImpl.java:101)
my.project.service.QuestionService.findCatItems(QuestionService.java:34)
我認為這可能是與我的JOINED
繼承相關的問題,但我得到了與TABLE_PER_CLASS
相同的錯誤。 你看到我做錯了嗎?
試試這種方式
Tag tag = tagDAO.findTagbyId(1);
q = "FROM QuestionText qt WHERE qt.tag = :tag";
query = (Query) session.createQuery(q);
query.setParameter("tag", tag);
List<QuestionText> data = query.list();
確保您的表格與Idtag具有相同的類型。 錯誤報告是什么:類型與Integer不匹配。
這些方法是根據bean命名約定命名的嗎? 我會說不。
嘗試setIdTag()和getIdTag()。
@Id
@GeneratedValue(strategy = IDENTITY)
@Column(name = "idtag", unique = true, nullable = false)
public Integer getIdtag() {
return this.idtag;
}
public void setIdtag(Integer idtag) {
this.idtag = idtag;
}
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