PHP-if語句在while循環中

Question

我在讓我的簡單if語句在PHP while循環內工作時遇到問題。 這是我的代碼：

$p=mysql_query("SELECT * FROM forum_posts WHERE forum_id='$cid' AND topic_id='$id' AND post_deleted='0' ORDER BY post_time ASC LIMIT  $offset, $rowsperpage");

while($post=mysql_fetch_assoc($p)){ 
    $userpost=$user->getUserData($post['userid']);

          if($userpost['specialmembership'] == 1){
            $pioneer = "True";
          }
echo $userpost['username'];
echo $pioneer;

}

因此，在上面的示例中，我有兩個不同的用戶。 它們分別命名為user1和user2 。

• User1具有特殊會員資格= 0
• User2具有特殊會員資格= 1

上面的代碼將輸出以下內容（此示例中的while循環被循環4次 ）：

它將輸出：

user1

user2
true

user1
true

user2
true

問題出在這里，該腳本在第三個循環中在user1上輸出true。 User1不應設置為true，只有user2才應該設置為true，因為他的specialmembership = 1;

怎么了

Answer 1

您應該添加一個else

if($userpost['specialmembership'] == 1){
      $pioneer = "True";
}else {
     $pioneer = "False";
}

因為一旦設置了$pioneer的值就不會更改（如果您不再這樣做）

Answer 2

將$pioneer設置為true后，您再也不會重置，因此第一個“ true”用戶之后的所有用戶也將為true。 您需要其他：

      if($userpost['specialmembership'] == 1){
        $pioneer = "True";
      } else {
        $pioneer = "False";  // <---you need this
      }

Answer 3

嘗試跟隨

$p=mysql_query("SELECT * FROM forum_posts WHERE forum_id='$cid' AND topic_id='$id' AND post_deleted='0' ORDER BY post_time ASC LIMIT  $offset, $rowsperpage");

while($post=mysql_fetch_assoc($p)){ 
    $userpost=$user->getUserData($post['userid']);

            $pioneer = "False";
          if($userpost['specialmembership'] == 1){
            $pioneer = "True";
          }
    echo $userpost['username'];
    echo $pioneer;
}

Answer 4

正如Andrewsi所說，每次進入循環時都應重置$pioneer變量。

while($post=mysql_fetch_assoc($p)){ 
  // defaults to 'False'
  $pioneer = 'False';
}

另一種選擇是引入else分支：

else {
  $pioneer = 'False';
}

此外，你不應該使用已棄用MySQL擴展了！ 切換到MySQLi（帶有准備好的語句）或PDO！

Answer 5

您無需在每個循環后重置$pioneer的值。 如果不應該將其重置為空字符串，則為"true" 。

while($post=mysql_fetch_assoc($p)){ 
    $userpost=$user->getUserData($post['userid']);
        if($userpost['specialmembership'] == 1){
            $pioneer = "true";
        }else{
            $pioneer = "";
    echo $userpost['username'];
    echo $pioneer;
}

Answer 6

寫

$p=mysql_query("SELECT * FROM forum_posts WHERE forum_id='$cid' AND topic_id='$id'      

AND post_deleted='0' ORDER BY post_time ASC LIMIT  $offset, $rowsperpage");

while($post=mysql_fetch_assoc($p)){ 
$userpost=$user->getUserData($post['userid']);
      $pioneer="False";
      if($userpost['specialmembership'] == 1){
        $pioneer = "True";
      }
echo $userpost['username'];
echo $pioneer;

}

Answer 7

您永遠不會重置$Pioneer變量

嘗試

$pioneer = $userpost['specialmembership'] == 1 ? "True" : "False or Whatever you want";

Answer 8

嘗試添加其他條件，例如

while($post=mysql_fetch_assoc($p)){ 
    $userpost=$user->getUserData($post['userid']);
          $pioneer = ($userpost['specialmembership'] == 1? "True": "False");
echo $userpost['username'];
echo $pioneer;
}

或在開頭定義$ pioneer =“ False”並使用您的代碼

while($post=mysql_fetch_assoc($p)){ 
$userpost=$user->getUserData($post['userid']);

      if($userpost['specialmembership'] == 1){
        $pioneer = "True";
      }
echo $userpost['username'];
echo $pioneer;

}