簡體   English   中英

使用$ db-> quote()使用IN進行Zend Update查詢

[英]Zend Update query with IN using $db->quote()

誰能告訴我我要去哪里錯了?

$tmp = array();
    $tmp[] = 'account';
    //$tmp[] = 'tomwased';
    //  $tmp = 'eshantsahu,account';
        $qu = $this->_db->quote($tmp);
    //  print_r($qu);
        $this->_db->update('user',array('password' => 'dddd'),array("username IN ( ? )"=> $qu));

嘗試使用下一個

$updateData = array('username' => 'newvalue');

$whereConditions = array();
$whereConditions[] = $this->_db->quoteInto('param1 = ?', 'val1');
$whereConditions[] = $this->_db->quoteInto('param2 IN (?)', array('val2','val3');
$whereConditions = join(" AND ", $whereConditions);

$this->_db->update($updateData, $whereConditions);

暫無
暫無

聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.

 
粵ICP備18138465號  © 2020-2024 STACKOOM.COM