在iOS中生成隨機字母數字字符串

Question

如何從ios中的給定String生成隨機的非重復（不重復相同字母）的字母數字字符串？

Answer 1

以下函數將獲取一個字符串並將其隨機化，通常來自輸入字符串的每個字符僅一次：

- (NSString *)randomizeString:(NSString *)str
{
    NSMutableString *input = [str mutableCopy];
    NSMutableString *output = [NSMutableString string];

    NSUInteger len = input.length;

    for (NSUInteger i = 0; i < len; i++) {
        NSInteger index = arc4random_uniform((unsigned int)input.length);
        [output appendFormat:@"%C", [input characterAtIndex:index]];
        [input replaceCharactersInRange:NSMakeRange(index, 1) withString:@""];
    }

    return output;
}

Answer 2

-(NSString *)randomStringWithLength: (int) len 

{

  NSString *letters = @"abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789";

   NSMutableString *randomString = [NSMutableString stringWithCapacity: len];

    for (int i=0; i<len; i++) 
{

         [randomString appendFormat: @"%C", [letters characterAtIndex: arc4random() % [letters length]]];
    }

    return randomString;
}`