左聯接多個表和條件

Question

我想對當前表所引用的另一個表中的值進行排序。 我的查詢如下所示：

SELECT o._id,
       o.titel,
       o.beschreibung
FROM   `objekt` AS o,
       `objekt_einzel` AS oe,
       `objekt_einzel_immobilie` AS oei,
       `objekt_art` AS oa,
       `verortung` AS v
       #here
       ,`person` AS p,
       `person_bauträger` AS pb
       #end
WHERE  o._id = oe.objekt_id
       AND oe._id = oei.objekt_einzel_id
       AND oa._id = o.objekt_art_id
       AND o.ort_id = v._id
       #here
       AND oe.bauträger_id = pb._id
       AND pb.person_id = p._id
       #end
       AND ( oei.justimmo_objekt_id = "0"
              OR oei.justimmo_objekt_id IS NULL
              OR oei.justimmo_objekt_id = "" )
#here
ORDER  BY p.firmenbezeichnung ASC

查詢工作正常，但它表明我只值如果oe.bauträger_id設置。 我也想要null值。 所以我需要左聯接。 我嘗試了不同的方法，但只收到諸如unknown column類的消息，或者得到了太多結果。

我試圖簡化為：

SELECT o._id,
       o.titel,
       o.beschreibung
FROM   `objekt` AS o,
       `objekt_einzel` AS oe,
        (SELECT oe.bauträger_id
        FROM objekt o, objekt_einzel oe, objekt_einzel_immobilie oei
        WHERE o._id = oe.objekt_id AND oe._id = oei.objekt_einzel_id) AS menge1
LEFT JOIN
        (SELECT pb._id AS bauträger_id
        FROM person p, person_bauträger pb
        WHERE p._id = pb.person_id) AS menge2
ON menge1.bauträger_id = menge2.bauträger_id
WHERE o._id = oe.objekt_id AND oe.bauträger_id = menge1.bauträger_id

但是在這里我得到了太大的結果集。 我不知道如何更好地解釋這一點。 數據集太大，無法創建示例。 我希望你明白我的意思。

Answer 1

SELECT o._id,
       o.titel,
       o.beschreibung
FROM   `objekt` AS o
       JOIN `objekt_einzel` AS oe ON o._id = oe.objekt_id
       JOIN `objekt_einzel_immobilie` AS oei ON oe._id = oei.objekt_einzel_id
       JOIN `objekt_art` AS oa ON o.objekt_art_id = oa._id
       JOIN `verortung` AS v ON o.ort_id = v._id
       LEFT JOIN `person_bauträger` AS pb ON oe.bauträger_id = pb._id
       LEFT JOIN `person` AS p ON pb.person_id = p._id
WHERE  oei.justimmo_objekt_id = "0"
       OR oei.justimmo_objekt_id IS NULL
       OR oei.justimmo_objekt_id = ""
ORDER  BY p.firmenbezeichnung ASC

第二次嘗試應該起作用，因為它只是使用JOIN語法和LEFT JOINs重寫的原始代碼。