[英]Drop-down box dependent on the option selected in another drop-down box
我在一個表單中有 2 個不同的 SELECT OPTION。
第一個是源,第二個是狀態。 我希望在我的狀態下拉列表中有不同的選項,具體取決於在我的源下拉列表中選擇的選項。
來源:
<select id="source" name="source">
<option>MANUAL</option>
<option>ONLINE</option>
</select>
地位:
<select id="status" name="status">
</select>
選項: - 如果來源為 MANUAL,則狀態為 OPEN 或 DELIVERED - 如果來源為 ONLINE,則狀態為 OPEN 或 DELIVERED 或 SHIPPED
我的非工作嘗試:
<script>
$(document).ready(function () {
var option = document.getElementById("status").options;
if (document.getElementById('source').value == "MANUAL") {
$("#status").append('<option>OPEN</option>');
$("#status").append('<option>DELIVERED</option>');
}
if (document.getElementById('source').value == "ONLINE") {
$("#status").append('<option>OPEN</option>');
$("#status").append('<option>DELIVERED</option>');
$("#status").append('<option>SHIPPED</option>');
}
});
</script>
嘗試這樣的事情...... jsfiddle演示
HTML
<!-- Source: -->
<select id="source" name="source">
<option>MANUAL</option>
<option>ONLINE</option>
</select>
<!-- Status: -->
<select id="status" name="status">
<option>OPEN</option>
<option>DELIVERED</option>
</select>
JS
$(document).on('ready', function () {
$("#source").on('change', function () {
var el = $(this);
if (el.val() === "ONLINE") {
$("#status").append("<option>SHIPPED</option>");
} else if (el.val() === "MANUAL") {
$("#status option:last-child").remove();
}
});
});
我發布這個答案是因為通過這種方式你將永遠不需要任何像 jQuery 和任何其他插件,這有通過簡單的 javascript 的解決方案。
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<script language="javascript" type="text/javascript">
function dynamicdropdown(listindex)
{
switch (listindex)
{
case "manual" :
document.getElementById("status").options[0]=new Option("Select status","");
document.getElementById("status").options[1]=new Option("OPEN","open");
document.getElementById("status").options[2]=new Option("DELIVERED","delivered");
break;
case "online" :
document.getElementById("status").options[0]=new Option("Select status","");
document.getElementById("status").options[1]=new Option("OPEN","open");
document.getElementById("status").options[2]=new Option("DELIVERED","delivered");
document.getElementById("status").options[3]=new Option("SHIPPED","shipped");
break;
}
return true;
}
</script>
</head>
<title>Dynamic Drop Down List</title>
<body>
<div class="category_div" id="category_div">Source:
<select id="source" name="source" onchange="javascript: dynamicdropdown(this.options[this.selectedIndex].value);">
<option value="">Select source</option>
<option value="manual">MANUAL</option>
<option value="online">ONLINE</option>
</select>
</div>
<div class="sub_category_div" id="sub_category_div">Status:
<script type="text/javascript" language="JavaScript">
document.write('<select name="status" id="status"><option value="">Select status</option></select>')
</script>
<noscript>
<select id="status" name="status">
<option value="open">OPEN</option>
<option value="delivered">DELIVERED</option>
</select>
</noscript>
</div>
</body>
</html>
更多細節,我的意思是動態和更多的依賴請看我的文章 創建動態下拉列表
在這個 jsfiddle 中,您會找到我設計的解決方案。 這個想法是在 html 中有一個選擇器對,並根據第一個選擇的選項使用(普通)javascript來過濾依賴選擇器中的選項。 例如:
<select id="continents">
<option value = 0>All</option>
<option value = 1>Asia</option>
<option value = 2>Europe</option>
<option value = 3>Africa</option>
</select>
<select id="selectcountries"></select>
用途(在 jsFiddle 中)
MAIN.createRelatedSelector
( document.querySelector('#continents') // from select element
,document.querySelector('#selectcountries') // to select element
,{ // values object
Asia: ['China','Japan','North Korea',
'South Korea','India','Malaysia',
'Uzbekistan'],
Europe: ['France','Belgium','Spain','Netherlands','Sweden','Germany'],
Africa: ['Mali','Namibia','Botswana','Zimbabwe','Burkina Faso','Burundi']
}
,function(a,b){return a>b ? 1 : a<b ? -1 : 0;} // sort method
);
[ Edit 2021 ] 或使用數據屬性,例如:
document.addEventListener("change", checkSelect); function checkSelect(evt) { const origin = evt.target; if (origin.dataset.dependentSelector) { const selectedOptFrom = origin.querySelector("option:checked") .dataset.dependentOpt || "n/a"; const addRemove = optData => (optData || "") === selectedOptFrom ? "add" : "remove"; document.querySelectorAll(`${origin.dataset.dependentSelector} option`) .forEach( opt => opt.classList[addRemove(opt.dataset.fromDependent)]("display") ); } }
[data-from-dependent] { display: none; } [data-from-dependent].display { display: initial; }
<select id="source" name="source" data-dependent-selector="#status"> <option>MANUAL</option> <option data-dependent-opt="ONLINE">ONLINE</option> <option data-dependent-opt="UNKNOWN">UNKNOWN</option> </select> <select id="status" name="status"> <option>OPEN</option> <option>DELIVERED</option> <option data-from-dependent="ONLINE">SHIPPED</option> <option data-from-dependent="UNKNOWN">SHOULD SELECT</option> <option data-from-dependent="UNKNOWN">MAYBE IN TRANSIT</option> </select>
function dropdownlist(listindex)
{
document.getElementById("ddlCity").options.length = 0;
switch (listindex)
{
case "Karnataka":
document.getElementById("ddlCity").options[0] = new Option("--select--", "");
document.getElementById("ddlCity").options[1] = new Option("Dharawad", "Dharawad");
document.getElementById("ddlCity").options[2] = new Option("Haveri", "Haveri");
document.getElementById("ddlCity").options[3] = new Option("Belgum", "Belgum");
document.getElementById("ddlCity").options[4] = new Option("Bijapur", "Bijapur");
break;
case "Tamilnadu":
document.getElementById("ddlCity").options[0] = new Option("--select--", "");
document.getElementById("ddlCity").options[1] = new Option("dgdf", "dgdf");
document.getElementById("ddlCity").options[2] = new Option("gffd", "gffd");
break;
}
}
* 州:--Select-- Karnataka Tamilnadu Andra pradesh Telngana
<div>
<p>
<label id="lblCt">
<span class="red">*</span>
City:</label>
<select id="ddlCity">
<!-- <option>--Select--</option>
<option value="1">Dharawad</option>
<option value="2">Belgum</option>
<option value="3">Bagalkot</option>
<option value="4">Haveri</option>
<option>Hydrabadh</option>
<option>Vijat vada</option>-->
</select>
<label id="lblCity"></label>
</p>
</div>
你最好做兩個selects
並顯示一個同時隱藏另一個。
它更容易,並且使用您的方法向selects
添加options
在 IE8 中不起作用(如果您關心)。
我希望以下代碼可以幫助或解決您的問題,或者您認為無法理解,請訪問http://phppot.com/jquery/jquery-dependent-dropdown-list-countries-and-states/ 。
HTML 動態依賴選擇
<div class="frmDronpDown">
<div class="row">
<label>Country:</label><br/>
<select name="country" id="country-list" class="demoInputBox" onChange="getState(this.value);">
<option value="">Select Country</option>
<?php
foreach($results as $country) {
?>
<option value="<?php echo $country["id"]; ?>"><?php echo $country["name"]; ?></option>
<?php
}
?>
</select>
</div>
<div class="row">
<label>State:</label><br/>
<select name="state" id="state-list" class="demoInputBox">
<option value="">Select State</option>
</select>
</div>
通過 AJAX 獲取狀態
<script> function getState(val) { $.ajax({
type: "POST",
url: "get_state.php",
data:'country_id='+val,
success: function(data){
$("#state-list").html(data);
}
});} </script>
使用 PHP 讀取狀態數據庫
<?php require_once("dbcontroller.php"); $db_handle = new DBController();if(!empty($_POST["country_id"])) {
$query ="SELECT * FROM states WHERE countryID = '" . $_POST["country_id"] . "'";
$results = $db_handle->runQuery($query); ?> <option value="">Select State</option><?php foreach($results as $state) { ?> <option value="<?php echo $state["id"]; ?>"><?php echo $state["name"]; ?></option><?php } } ?>
為此,我注意到顯示和隱藏標簽比為 DOM 添加和刪除標簽要好得多。 它的性能更好。
應該更新答案以替換已失效的函數.change
& .ready
$(document).on('ready',function() {
$("#source").on('change', function(){
var el = $(this);
if (el.val() === "ONLINE") {
$("#status").append("<option>SHIPPED</option>");
} else if (el.val() === "MANUAL") {
$("#status option:last-child").remove();
}
});
});
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