使用PDO將數據插入mysql，返回錯誤HY093

Question

我在編碼時真的很模糊，並且似乎無法找出導致我從使用PDO將數據插入到mysql的HY093錯誤的原因

function whatever($post_id, $comment) {
...
$query = "INSERT INTO `comments` (`id`, `post_id`, `comment`) VALUES (:id, post_id,:comment)";
$sql = $db->prepare($query);
$check = $sql->execute(array(':id'=>'',
                             ':post_id'=>$post_id,
                             ':comment'=>$comment));

//verify if data is inserted
if($check) {
    $test = 'inserted';
} else {
    $test = $sql->errorCode();
}
    return $test;
}

我收到此錯誤HY093 。

我的id是自動遞增的，我不確定是否使用''是聲明它的正確方法。

Answer 1

您在post_id之前忘記了:

$query = "INSERT INTO `comments` (`id`, `post_id`, `comment`) 
          VALUES (:id, :post_id, :comment)";
                       ^---------------------------here

Answer 2

代替 ：

`$query = "INSERT INTO `comments` (`id`, `post_id`, `comment`) VALUES (:id, post_id,:comment)";`

采用：

`$query = "INSERT INTO `comments` (`id`, `post_id`, `comment`) VALUES (:id, :post_id,:comment)";`

Answer 3

您可以使用NULL：

$query = "INSERT INTO `comments` (`id`, `post_id`, `comment`) VALUES (NULL, :post_id,:comment)";

或直接離開：

$query = "INSERT INTO `comments` (`post_id`, `comment`) VALUES (:post_id,:comment)";

然后：

$check = $sql->execute(array(':post_id'=>$post_id,
                             ':comment'=>$comment));

Answer 4

如果您的ID是自動增加的，請不要從php腳本發送值

    function whatever($post_id, $comment) {

     $query = "INSERT INTO `comments` ( `post_id`, `comment`)    VALUES(:id,post_id,:comment)";
       $sql = $db->prepare($query);
   $check = $sql->execute(array(':post_id'=>$post_id,':comment'=>$comment));

  //verify if data is inserted
  if($check) {
  $test = 'inserted';
  } else {
   $test = $sql->errorCode();
 }
  return $test;
}