基於多維數組制作關聯值數組的最佳方法

Question

我需要的是，當我單擊某個單元格（例如包含“ PMS03”的單元格[2,2]）時，我想要一個顯示所有包含PMS03的單元格的警報，這將是alert（“ Positions：[2 ，1]，[2,2]，[3,7]“）；

我認為在創建“ pointmapS”（= puntmapS）的過程中我會以某種方式創建第二個數組，但是我認為最好的辦法是讓像你們這樣的專家來幫助我，因為應該有很多我可能不知道的解決方案（效率更高）。

創建映射數組：

var jPunten = JSON.parse(data); 
var puntmapS = []; 
var cardsS = []; 
var prevCard = jPunten[0].KARTNR; //previous card starts with the first card
cardsS[0] = jPunten[0].KARTNR;
//Generate point arrays
for (var i=0;i<jPunten.length;i++)
{
    if(prevCard!=jPunten[i].KARTNR){
        // (fill in cardsS, saves kartnr of the rows) gap-safety for if there should be gaps in the KARTNR's, currently only used for scounter
        cardsS[sCounter+1]=jPunten[i].KARTNR;sCounter++;
    } 
    //create an array under key jPunten[i].KARTNR, if it doesn't exist already
    puntmapS[sCounter] = puntmapS[sCounter] || []; // to avoid gaps we use sCounter instead of jPunten[i].KARTNR
    //then, assign your value
    console.log("S|| prevCard: "+ prevCard + " === " + jPunten[i].KARTNR +" (Kartnr)");

    puntmapS[sCounter][jPunten[i].BITNRK-1] = jPunten[i].STATDEV; //add point to row, -1 because array starts at 0

    console.log("S|| "+"  --SCounter: "+ sCounter + " bit: " + jPunten[i].BITNRK + "    = " + jPunten[i].STATDEV);
}

創建表：

if(puntmapS.length!=0){
    table = "<table style='margin-left:20px;font-size:80%;' border='1'><tbody><tr><th></th><th>1</th><th>2</th><th>3</th><th>4</th><th>5</th><th>6</th><th>7</th><th>8</th><th>9</th><th>10</th><th>11</th><th>12</th><th>13</th><th>14</th><th>15</th><th>16</th></tr><tr><th>"+cardsS[0]+ " S</th>";
    for (var i=0;i<sCounter+1;i++)
    {
        for (var x=0;x<16;x++)
        {
            if(puntmapS[i][x]!=undefined)
            {
                table+= "<td><a href='#' onClick='alert(\""+puntmapS[i][x]+"\")'>"+puntmapS[i][x]+"</a></td>";
            }
            else
            {
                table += "<td style='background-color:#E6E6E6'><a href='#' onClick='alert(\"EMPTY\")'>&nbsp;</a></td>";
            }
        }
        if(i<(sCounter)){
            table+="</tr><tr><th>"+(cardsS[i+1])+" S</th>";
        }
    }
    table += "</tr></table>";
}

jPunten看起來像這樣：

0
    Object { 0="LSZ09 ", 1="1", 2="S", more...} 
0
    "LSZ09 "    
1
    "1" 
2
    "S" 
3
    "0" 
4
    "1" 
5
    "0" 
6
    "I "    
BITNRK
    "1" 
BITSTATUS
    "0" 
DEVPKT
    "1"
KARTNR
    "0"
PKTTYP
    "S"
STATDEV
    "LSZ09 "    
TYPE
    "I "

Answer 1

我的主要建議是使用underscoreJS ，因為它具有用於操縱數組的許多有用的輔助函數，從而節省了很多鍵入操作。 作為您要解決的特定問題的解決方案，可以使用以下方法：

var arr = [['a', undefined], ['b', 'a']] //2x2 2D test array
var result = _.chain(arr) //Create chainable underscore object
    .map(function(row, j){ //map cell values to objects containing both the value and position in the array
        return _.map(row, function(cell, i){
            return { pos: [i,j], value: cell };
        })
    })
    .flatten() //Put all cells in a single array
    .filter(function(cell){ //Filter the cells based on some criterium
        return cell.value === 'a';
    })
    .map(function(cell){ //Return the position rather than the object we generated
        return cell.pos;
    })
    .value(); //Return the original array instead of the chainable underscore object

Answer 2

您可以創建一個關聯數組，其中鍵為“ PMSO3”，值是一個包含位置數組的對象。

map = [];
map['PMSO3'] = {
    label: 'PMS03-100',
    id: 124,
    positions: [{
        x: 2,
        y: 1
    }, {
        x: 2,
        y: 2
    }, {
        x: 3,
        y: 7
    }]
};

console.log('PMSO3 is located at these positions\n');
map['PMSO3'].positions.forEach(function(aPosition){
    console.log(aPosition.x+' '+aPosition.y+',');
});

的jsfiddle