zend framework 2 +自定義路由

Question

我嘗試遵循該主題的建議： zend framework 2 +路由數據庫

我有一個路線課：

    namespace Application\Router;

use Zend\Mvc\Router\Http\RouteInterface;
use Zend\ServiceManager\ServiceLocatorAwareInterface;
use Zend\Mvc\Router\RouteMatch;

class Content implements RouteInterface, ServiceLocatorAwareInterface {

protected $defaults = array();
protected $routerPluginManager = null;

public function __construct(array $defaults = array()) {
    $this->defaults = $defaults;
}

public function setServiceLocator(\Zend\ServiceManager\ServiceLocatorInterface $routerPluginManager) {
    $this->routerPluginManager = $routerPluginManager;
}

public function getServiceLocator() {
    return $this->routerPluginManager;
}

public static function factory($options = array()) {
    if ($options instanceof \Traversable) {
        $options = ArrayUtils::iteratorToArray($options);
    } elseif (!is_array($options)) {
        throw new InvalidArgumentException(__METHOD__ . ' expects an array or Traversable set of options');
    }

    if (!isset($options['defaults'])) {
        $options['defaults'] = array();
    }

    return new static($options['defaults']);
}

public function match(Request $request, $pathOffset = null) {
    if (!method_exists($request, 'getUri')) {
        return null;
    }

    $uri = $request->getUri();
    $fullPath = $uri->getPath();

    $path = substr($fullPath, $pathOffset);
    $alias = trim($path, '/');

    $options = $this->defaults;
    $options = array_merge($options, array(
        'path' => $alias
            ));

    return new RouteMatch($options);
}

public function assemble(array $params = array(), array $options = array()) {
    if (array_key_exists('path', $params)) {
        return '/' . $params['path'];
    }

    return '/';
}

public function getAssembledParams() {
    return array();
}

}

請注意match（）函數返回Zend \\ Mvc \\ Router \\ RouteMatch實例的對象，但是在文件Zend \\ Mvc \\ Router \\ Http \\ TreeRouteStack中，它檢查對象是否是RouteMatch的實例（沒有命名空間的前綴）

if (
    ($match = $route->match($request, $baseUrlLength, $options)) instanceof RouteMatch
            && ($pathLength === null || $match->getLength() === $pathLength)
        )

在我的情況下，條件由於名稱空間而失敗。

有什么建議么？

Answer 1

好的，我知道了問題所在。 我應該返回Zend \\ Mvc \\ Router \\ Http \\ RouteMatch而不是返回Zend \\ Mvc \\ Router \\ RouteMatch

這解決了我的問題