[英]Android - Insert row into SQLite DB
我在將行插入數據庫表時遇到問題。 我下面的代碼:
try {
myDB = jDB.getInstance(getApplicationContext()).db;
myDB.beginTransaction();
String sSQL = "INSERT INTO kosik (mnozstvi, cena, idVyrobek) VALUES ('" +
sMn + "', '" + sCena + "', '" + String.valueOf(iIDVyrobku) + "');";
myDB.execSQL(sSQL, null);
myDB.endTransaction();
} catch (SQLiteException e) {
e.printStackTrace();
}
jDB類如下:
public class jDB {
private static jDB dbInstance = null;
public static String DB_PATH;
public static SQLiteDatabase db = null;
private static final String DATABASE_NAME = "db.sqlite";
.
.
.
public static jDB getInstance(Context context)
{
if (dbInstance == null)
{
DB_PATH = "/data/data/" + context.getPackageName();
// if not exists database, copy new from assets
if (!isDataBaseExist())
{
try {
copyDataBase(context);
} catch (IOException ex)
{
Toast.makeText(context,
"" + ex.getLocalizedMessage(), Toast.LENGTH_LONG).show();
}
}
DB_PATH = DB_PATH + "/" + DATABASE_NAME;
db = SQLiteDatabase.openDatabase(DB_PATH, null, SQLiteDatabase.OPEN_READWRITE);
// create singleton object
dbInstance = new jDB(context);
}
return dbInstance;
}
插入后,一切似乎正常,但表中未插入任何行...
我做錯了什么?
謝謝,彼得
解:
最后,有可行的解決方案:
try {
myDB = jDB.getInstance(getApplicationContext()).db;
myDB.beginTransaction();
ContentValues insertValues = new ContentValues();
insertValues.put("idVyrobek", String.valueOf(iIDVyrobku));
insertValues.put("mnozstvi", sMn);
insertValues.put("cena", sCena);
insertValues.put("poznamka", "");
myDB.insertOrThrow("kosik", null, insertValues);
myDB.setTransactionSuccessful();
} catch (SQLiteException e) {
e.printStackTrace();
} finally {
myDB.endTransaction();
}
非常感謝您對Bismark的幫助!
嘗試在調用endTransaction()之前添加setTransactionSuccessful()。 另外,我通常將endTransaction放在finally語句中,以避免SQLite出現問題:
myDB = jDB.getInstance(getApplicationContext()).db;
myDB.beginTransaction();
try {
String sSQL = "INSERT INTO kosik (mnozstvi, cena, idVyrobek) VALUES ('" +
sMn + "', '" + sCena + "', '" + String.valueOf(iIDVyrobku) + "');";
myDB.execSQL(sSQL, null);
myDB.setTransactionSuccessful();
} catch (SQLiteException e) {
e.printStackTrace();
} finally {
myDB.endTransaction();
}
聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.