Android：獲取圖像的URI時出錯

Question

在我的Android應用程序中有一個圖像視圖。 我需要獲取此圖像並將其保存在sqlite數據庫中。 我試圖獲取圖像的uri並將其保存在數據庫中。 我已經使用以下代碼段來獲取圖像的uri。

// get byte array from image view
        Drawable d = image.getBackground();
        BitmapDrawable bitDw = ((BitmapDrawable) d);
        Bitmap bitmap = bitDw.getBitmap();
        ByteArrayOutputStream stream = new ByteArrayOutputStream();
        bitmap.compress(Bitmap.CompressFormat.JPEG, 100, stream);
        byte[] imageInByte = stream.toByteArray();

        //get URI from byte array
        String path = null;
        try {
            path = Images.Media.insertImage(getContentResolver(), imageInByte.toString(),
                    "title", null);
        } catch (FileNotFoundException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        }

        Uri imageUri = Uri.parse(path);

        String uriString = imageUri.toString() ;
        System.out.println(uriString);

        ContentValues values = new ContentValues();
        values.put(COLUMN_PROFILE_PICTURE, uriString);

但是原木貓說

11-12 06:54:21.028: E/AndroidRuntime(863): FATAL EXCEPTION: main
11-12 06:54:21.028: E/AndroidRuntime(863): java.lang.ClassCastException: android.graphics.drawable.GradientDrawable cannot be cast to android.graphics.drawable.BitmapDrawable

錯誤指向此行。

BitmapDrawable bitDw = ((BitmapDrawable) d);

Answer 1

該問題在ClassCastException中指出，您不能將GradientDrawable 強制轉換為BitmapDrawable 。

這是解決方法：

    ...

    Drawable d = image.getBackground();
    GradientDrawable bitDw = ((GradientDrawable) d);  // the correct cast

    // create a temporary Bitmap and let the GradientDrawable draw on it instead
    Bitmap bitmap = Bitmap.createBitmap(image.getWidth(),
            image.getHeight(), Config.ARGB_8888);
    Canvas canvas = new Canvas(bitmap);
    bitDw.setBounds(0, 0, canvas.getWidth(), canvas.getHeight());
    bitDw.draw(canvas);

    // Bitmap bitmap = bitDw.getBitmap(); // obsoleted code

    ByteArrayOutputStream stream = new ByteArrayOutputStream();
    bitmap.compress(Bitmap.CompressFormat.JPEG, 100, stream);
    byte[] imageInByte = stream.toByteArray();

    ...