PHP將日期范圍分為2個單獨的范圍

Question

我想知道是否可以將某個日期范圍划分為2個單獨的日期范圍（如果滿足某些特定條件）？

我正在建立一個假期預訂系統，如果假期預訂超過2年，則需要拆分日期。 例：

start date: 22-12-2013
end date: 04-01-2014

有了上面的日期，我想將它們分成2個日期范圍，所以我最終會得到這樣的結果：

start date: 22-12-2013
end date: 31-12-2013

接着：

start date: 01-01-2014
end date: 04-01-2014

這可能嗎？ 如果可以的話，有人可以指出我在Google中需要搜索的正確方向嗎？

Answer 1

這是一種非常基本的方法，但是我認為研究如下內容可能會很有趣：

$date1 = '22-12-2013';
$date2 = "04-01-2014";

function split_date($d1, $d2)
{
    $start_year = substr($d1, -4);
    $end_year = substr($d2, -4);

    if($end_year > $start_year)
    {
    $d1 .= ' ['.date('d-m-Y',strtotime("last day of December".$start_year)).'] <br />';
    $d2 = '['.date('d-m-Y',strtotime("first day of January".$start_year)).'] ' . $d2;
    }
    return $d1 . $d2;
}

echo split_date($date1, $date2);

http://www.php.net/manual/en/datetime.formats.relative.php

Answer 2

如果您想拆分更多月，可以使用此功能：

function getMonthRanges($start, $end) {
    $timeStart = strtotime($start);
    $timeEnd   = strtotime($end);
    $out       = [];

    $milestones[] = $timeStart;
    $timeEndMonth = strtotime('first day of next month midnight', $timeStart);
    while ($timeEndMonth < $timeEnd) {
        $milestones[] = $timeEndMonth;
        $timeEndMonth = strtotime('+1 month', $timeEndMonth);
    }
    $milestones[] = $timeEnd;

    $count = count($milestones);
    for ($i = 1; $i < $count; $i++) {
        $out[] = [
            'start' => $milestones[$i - 1], // Here you can apply your formatting (like "date('Y-m-d H:i:s', $milestones[$i-1])") if you don't won't want just timestamp
            'end'   => $milestones[$i] - 1
        ];
    }

    return $out;
}

使用：

$result = getMonthRanges('15-11-2014', '19-11-2014');

結果：

Array
(
    [0] => Array
        (
            [start] => 1418594400
            [end] => 1420063199
        )

    [1] => Array
        (
            [start] => 1420063200
            [end] => 1422741599
        )

    [2] => Array
        (
            [start] => 1422741600
            [end] => 1425160799
        )

    [3] => Array
        (
            [start] => 1425160800
            [end] => 1426715999
        )

)

可讀的結果：

array_walk_recursive($result, 'applyFormat');

function applyFormat(&$item)
{
    $item = date('Y-m-d H:i:s', $item);
}

Array
(
    [0] => Array
        (
            [start] => 2014-12-15 00:00:00
            [end] => 2014-12-31 23:59:59
        )

    [1] => Array
        (
            [start] => 2015-01-01 00:00:00
            [end] => 2015-01-31 23:59:59
        )

    [2] => Array
        (
            [start] => 2015-02-01 00:00:00
            [end] => 2015-02-28 23:59:59
        )

    [3] => Array
        (
            [start] => 2015-03-01 00:00:00
            [end] => 2015-03-18 23:59:59
        )

)

Answer 3

感謝ilpaijin，這就是我想出的：

$date1 = '22-12-2013';
$date2 = "04-01-2014";

function split_date($d1, $d2)
{
    $start_year = substr($d1, -4);
    $end_year = substr($d2, -4);

    if($end_year > $start_year)
    {
    $d1 .= ' ['.date('d-m-Y',strtotime("31-12-".$start_year)).'] <br />';
    $d2 = '['.date('d-m-Y',strtotime("01-01-".$start_year."+1 years")).'] ' . $d2;
    }
    return $d1 . $d2;
}

echo split_date($date1, $date2);

Answer 4

如果有人想將日期范圍划分為任何年份，請執行以下操作。

$date1 = '22-12-2013';
$date2 = '04-01-2017';
$dA = array();

function split_date($d1, $d2, &$dA)
{
    $start_year = substr($d1, -4);
    $end_year = substr($d2, -4);

    if($end_year > $start_year)
    {
    $dA[] = $d1;    
        $dA[] = date('d-m-Y',strtotime("31-12-".$start_year));
        if($end_year - $start_year == 1)
        {
            $dA[] = date('d-m-Y',strtotime("01-01-".$start_year."+1 years"));
            $dA[] = $d2;
        }else
        {
            split_date(date('d-m-Y',strtotime("01-01-".$start_year."+1 years")), $d2, $dA);
        }
    }else if($end_year == $start_year)
    {
        $dA[] = $d1;
        $dA[] = $d2;
    }
}

split_date($date1, $date2, $dA);
print_r($dA);


//Answer

Array
(
[0] => 22-12-2013
[1] => 31-12-2013
[2] => 01-01-2014
[3] => 31-12-2014
[4] => 01-01-2015
[5] => 31-12-2015
[6] => 01-01-2016
[7] => 31-12-2016
[8] => 01-01-2017
[9] => 04-01-2017
)

Answer 5

很簡單的方法。 您可以拆分日期范圍支持所有類型的日期格式。

function split_date($start_date,$end_date){

    while($start_date < $end_date){
        $end = date("Y-m-d", strtotime("Last day of December", strtotime($start_date)));
        if($end_date<$end){
            $end = $end_date;
        }
        $dates[] =array('start'=>$start_date,'end'=>$end);

        $start_date =date("Y-m-d", strtotime("+1 day", strtotime($end)));

    }
    return $dates; 
}
$dates = split_date('2011-01-02','2013-01-04');
print_r($dates);

OUPTPUT

Array
(
    [0] => Array
        (
            [start] => 2011-01-02   //start date
            [end] => 2011-12-31
        )

    [1] => Array
        (
            [start] => 2012-01-01
            [end] => 2012-12-31
        )

    [2] => Array
        (
            [start] => 2013-01-01
            [end] => 2013-01-04  //end date
        )

)