[英]How to call the arraylist variable from one class to another class in android
我有疑問,如何在Android中將arraylist變量從一個類調用到另一個類,我是json服務的arryalist形式的框架,我在很多方面嘗試過,但我不知道如何從一個類調用數組列表去另一個班級。 我使用以下代碼。 使用HashMap構建數組列表,請提前幫助我,Thnaks。
下面顯示的是FirstActivityCLass
protected Integer doInBackground(Void... arg0) {
try {
JSONObject e = null;
System.out.println("In Background...");
StrictMode.ThreadPolicy policy = new StrictMode.ThreadPolicy.Builder()
.detectAll().penaltyLog().build();
StrictMode.setThreadPolicy(policy);
String API = "http://traininglabs.com/nic/a-remainders-list.php?email="+email;
System.out.println(API);
JSONObject loginjson = JSONfunctions1.getJSONfromURL(API);
responseArray=loginjson.getJSONArray("user");
mylist=new ArrayList<HashMap<String,String>>();
for (int i = 0; i < responseArray.length(); i++)
{
map = new HashMap<String, String>();
JSONObject obj= responseArray.getJSONObject(i);
**String ss = obj.getString("id");
map.put("id", obj.getString("id"));**
map.put("state", obj.getString("status"));
map.put("entity", obj.getString("company"));
map.put("date", obj.getString("adate"));
s1 = e.getString("state");
s2 = e.getString("entity");
s3 = e.getString("date");
System.out.println("this is string--->" + ss);
mylist.add(map);
}
} catch (Exception e) {
Log.d("Error", "Error in API" + e.getStackTrace().toString());
return 1;
}
return 0;
}
這是我的ArryaList的第二個Activity參數是id
protected Integer doInBackground(Void... arg0) {
System.out.println("In Background...");
StrictMode.ThreadPolicy policy = new StrictMode.ThreadPolicy.Builder()
.detectAll().penaltyLog().build();
StrictMode.setThreadPolicy(policy);
try {
String ssp_state = sp_state.getSelectedItem().toString();
String ssp_entity = sp_entity.getSelectedItem().toString();
String ssp_date = sp_date.getText().toString();
String ssp_time = sp_time.getText().toString();
String API = "http://traininglabs.com/projects/nic/a-edit-remainder.php?id="+**id**+ "&email="+ mail_str+ "&sid="+ sp_id+ "entity="+ ssp_entity+datetime="+ ssp_date+ ssp_time;
System.out.println(API);
JSONArray loginjson = JSONfunctions.getJSONfromURL(API);
Log.d(TAG, "JSON_RES" + loginjson);
return 0;
} catch (Exception e) {
Log.d("Error", "Error in API" + e.getStackTrace().toString());
return 1;
} // return null;
}
使其成為全球性的,或者將其置於單一的,更復雜但持久的方式,因為您處理網絡通過共享首選項共享它。
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