SQL查詢按時間間隔進行分組

Question

我有一個查詢，它根據時間返回記錄，例如

+-------------+--------------+
| RenewalTime | RenewalCount |
+-------------+--------------+
|           1 |         2345 |
|           2 |          189 |
|           3 |          789 |
|           4 |         7676 |
|           5 |         9876 |
|           6 |         9762 |
+-------------+--------------+

但是我想像下面這樣顯示它，其中它基於5分鍾組顯示數據

+-------------+--------------+
| RenewalTime | RenewalCount |
+-------------+--------------+
| 0-5         |         2345 |
| 5-10        |          189 |
+-------------+--------------+

Select Round((Cast(i.Modification_Date As Date) - Cast(Refill_Date As Date)) * 24 *     60,0) RenewalTime, count(1) RenewalCount
from refill,subscription_interval i where Trunc(Refill_Date) > '18-Nov-13'
And (Cast(i.Modification_Date As Date) - Cast(Refill_Date As Date)) * 24 * 60 > 0
and (cast(i.modification_date as date) - cast(refill_date as date)) * 24 * 60 < 1000
group by Round((Cast(i.Modification_Date As Date) - Cast(Refill_Date As Date)) * 24 * 60,0)
order by RenewalTime;

Answer 1

您可以嘗試以下邏輯：

SELECT
      CASE
          WHEN YOURCOL1 <= 5
          THEN
              '1-5'
          WHEN YOURCOL1 <= 10
          THEN
              '6-10'
          ELSE
              'others'
      END
          AS YOURCOL1,
      COUNT ( YOURCOL2 ) AS N
FROM
      YOURTABLE
GROUP BY
      CASE
          WHEN YOURCOL1 <= 5
          THEN
              '1-5'
          WHEN YOURCOL1 <= 10
          THEN
              '6-10'
          ELSE
              'others'
      END;

Answer 2

我認為該查詢可以創建您想要的東西：

select to_char((t1.RenewalTime-1)*5)|| '-' ||to_char(t1.RenewalTime*5) as RenewalTime,RenewalCount 
 from
  (Select Round((Cast(i.Modification_Date As Date) - Cast(Refill_Date As Date)) * 24 *     60,0) RenewalTime, count(1) RenewalCount
  from refill,subscription_interval i where Trunc(Refill_Date) > '18-Nov-13'
  And (Cast(i.Modification_Date As Date) - Cast(Refill_Date As Date)) * 24 * 60 > 0
  and (cast(i.modification_date as date) - cast(refill_date as date)) * 24 * 60 < 1000
  group by Round((Cast(i.Modification_Date As Date) - Cast(Refill_Date As Date)) * 24 * 60,0)
  order by RenewalTime)t1
where t1.RenewalTime < 3;

Answer 3

我可以將RenewTime轉換為5分鍾間隔，如下所示：

((cast(i.modification_date as date) - cast(refill_date as date)) * 24 * 60 /5

接下來，我將使用下限功能將一個5分鍾的小組與另一個小組區分開：

floor((cast(i.modification_date as date) - cast(refill_date as date)) * 24 * 60/ 5)

接下來，我將其轉換為RenewalTime列所需的文本，如下所示：

to_char( 5 * floor((cast(i.modification_date as date) - cast(refill_date as date)) * 24 * 60/ 5)) ||' - ' || to_char( 5 * (floor((cast(i.modification_date as date) - cast(refill_date as date)) * 24 * 60/ 5)+1))

間隔是這樣的：

0 <=更新時間<5 ==>'0-5'

5 <=續約時間<10 ==>'5-10'

10 <=續約時間<15 ==> '10-15'

15 <=續約時間<20 ==> '15-20'

這將導致此sql語句。

select
to_char( 5 * floor((cast(i.modification_date as date) - cast(refill_date as date)) * 24 * 60/ 5)) || ' - ' || to_char( 5 * (floor((cast(i.modification_date as date) - cast(refill_date as date)) * 24 * 60/ 5) +1)) RenewalTime
   count(1) renewal_count
from refill,
   subscription_interval i
where trunc(refill_date) > to_date('18-nov-13', 'dd-mon-yy')
   and (cast(i.modification_date as date) - cast(refill_date as date)) * 24 * 60 > 0
   and (cast(i.modification_date as date) - cast(refill_date as date)) * 24 * 60 < 1000
group by
to_char( 5 * floor((cast(i.modification_date as date) - cast(refill_date as date)) * 24 * 60/ 5)) || ' - ' || to_char( 5 * floor((cast(i.modification_date as date) - cast(refill_date as date)) * 24 * 60/ 5) +1)
order by 1;