[英]SQL Sum with non unique date
我正在嘗試編寫一個SQL查詢,該查詢將匯總以下兩個示例表中的總產量:
Table: CaseLots
DateProduced kgProduced
October 1, 2013 10000
October 1, 2013 10000
October 2, 2013 10000
Table: Budget
OperatingDate BudgetHours
October 1, 2013 24
October 2, 2013 24
我想輸出如下表:
TotalProduction TotalBudgetHours
30000 48
到目前為止,這是我所擁有的代碼:
SELECT
Sum(kgProduced) AS TotalProduction, Sum(BudgetHours) AS TotalBudgetHours
FROM
dbo.CaseLots INNER JOIN dbo.Budget ON dbo.CaseLots.DateProduced = dbo.Budget.OperatingDate
WHERE
dbo.Budget.OperatingDate BETWEEN '2013-10-01' AND '2013-10-02'
在一天中產生多個案件的情況下,查詢似乎是預算小時的兩倍。 我得到的表如下:
Total Production BudgetHours
30000 72
我該如何解決?
想想INNER JOIN在做什么。
對於CaseLot中的每一行,它會在Budget中找到具有匹配日期的任何行。
如果要刪除SQL中的聚合語句,而僅顯示內部聯接,則會看到以下結果集:
日期生產的公斤生產的經營日期預算小時
2013年10月1日10000 2013年10月1日24
2013年10月1日10000 2013年10月1日24
2013年10月2日10000 2013年10月2日24
(該死的StackOverflow,為什么你沒有Markdown的表:()
在此基礎上運行聚合很容易看到您如何獲得72小時的結果。
正確的查詢需要首先聚合CaseLots表,然后再聯接到Budget表。
SELECT DateProduced, TotalKgProduced, SUM(BudgetHours) AS TotalBudgetHours
FROM
(
SELECT DateProduced, SUM(kgProduced) AS TotalKgProduced
FROM CaseLots
GROUP BY DateProduced
) AS TotalKgProducedByDay
INNER JOIN
Budget
ON TotalKgProducedByDay.DateProduced = Budget.OperatingDate
WHERE DateProduced BETWEEN '1 Oct 2013' AND '2 Oct 2013'
GROUP BY DateProduced
問題在於INNER JOIN
產生3行表,因為所有鍵都匹配。 因此,存在三個“ 24”,總和為72。
要解決此問題,將其分為兩個查詢可能會更容易。
SELECT Sum(kgProduced) AS TotalProduction
FROM dbo.CaseLots
WHERE dbo.CaseLots.OperatingDate BETWEEN '2013-10-01' AND '2013-10-02'
LEFT JOIN
SELECT Sum(BudgetHours) AS TotalBudgetHours
FROM dbo.Budget
WHERE dbo.Budget.OperatingDate BETWEEN '2013-10-01' AND '2013-10-02'
這可以通過以下方式輕松實現:
SELECT
(SELECT SUM(kgProduced) FROM dbo.CaseLots WHERE DateProduced BETWEEN '2013-10-01' AND '2013-10-02') AS TotalProduction,
(SELECT SUM(BudgetHours) FROM dbo.Budget WHERE OperatingDate BETWEEN '2013-10-01' AND '2013-10-02') AS TotalBudgetHours
無需加入兩個表。
嘗試這個:
select DateProduced,TotalProduction,TotalBudgetHours from
(select DateProduced,sum(kgProduced) as TotalProduction
from CaseLots group by DateProduced) p
join
(select OperatingDate,sum(BudgetHours) as TotalBudgetHours
from Budget group by OperatingDate) b
on (p.DateProduced=b.OperatingDate)
where p.DateProduced between '2013-10-01' AND '2013-10-02'
對於這種特殊情況,其他答案更為簡單。 但是,如果你需要SUM
在10個不同的值CaseLots
表,你需要10個不同的子查詢。 以下是一個通用的,可擴展的解決方案:
SELECT
SUM(DayKgProduced) AS TotalProduction,
SUM(BudgetHours) AS TotalBudgetHours
FROM (
SELECT
DateProduced,
SUM(kgProduced) AS DayKgProduced,
FROM dbo.CaseLots
WHERE DateProduced BETWEEN '2013-10-01' AND '2013-10-02'
GROUP BY DateProduced
) DailyTotals
INNER JOIN dbo.Budget b ON DailyTotals.DateProduced = b.OperatingDate
首先,你SUM
生產的每一個CaseLot
不必SUM
的BudgetHours。 如果在上面的查詢中使用SELECT * FROM
,則會看到:
Date DayKgProduced BudgetHours
2013-10-01 20000 24
2013-10-02 10000 24
但是,您需要總計,因此我們將這些每日值SUM
,正確得出:
TotalProduction TotalBudgetHours
30000 48
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