[英]wordpress, get category names for a custom post type
有沒有更好的方法來獲取wordpress中自定義帖子類型的類別名稱?
<?php // get the portfolio categories
$terms = get_the_terms( $post->ID, 'filters' );
if ( $terms && ! is_wp_error( $terms ) ) :
$names = array();
$slugs = array();
foreach ( $terms as $term ) {
$names[] = $term->name;
$slugs[] = $term->slug;
}
$name_list = join( " / ", $names );
$slug_list = join( " category-", $slugs );
endif;
?>
<!-- BEGIN portfolio-item-->
<li class="portfolio-item third column category-<?php echo $slug_list; ?>" data-filter="category-<?php echo $slug_list; ?>">
<?php
$taxonomy = 'filters';
$terms = get_terms($taxonomy);
if ( $terms && !is_wp_error( $terms ) ) :
?>
<ul>
<?php foreach ( $terms as $term ) { ?>
<li><a href="<?php echo get_term_link($term->slug, $taxonomy); ?>"><?php echo $term->name; ?></a></li>
<?php } ?>
</ul>
<?php endif;?>
或者在fuctions.php中這樣:
function get_the_category_custompost( $id = false, $tcat = 'category' ) {
$categories = get_the_terms( $id, $tcat );
if ( ! $categories )
$categories = array();
$categories = array_values( $categories );
foreach ( array_keys( $categories ) as $key ) {
_make_cat_compat( $categories[$key] );
}
return apply_filters( 'get_the_categories', $categories );
}
並將該函數調用為:
<?php $cat = get_the_category_custompost($post->ID, 'Your Custom Taxonomy'); ?>
我的回答似乎太簡單了,但是我用這個來列出一個名為DW Question Answer的wordpress插件中的類別,它與標准的wp類別有不同的類別。
我假設Design Wall使用自定義帖子類型來創建q&a部分和分類法來創建類別。
<ul>
<?php wp_list_categories('taxonomy=dwqa-question_category&hide_empty=0&orderby=id&title_li=');?>
</ul>
假設您的自定義分類是recipegroups,我已經在functions.php中實現並測試了這段代碼,我相信它也適用於插件。
$recipeTerms = get_terms(array(
'taxonomy' => 'recipegroups',
));
foreach($recipeTerms as $recipeTerm){
if($recipeTerm->parent==0){
echo "<div class='termsBox'>"; // remove these div's to suit your needs..
$termLink =get_term_link( $recipeTerm );
echo "<a href='$termLink'><div class='termParent'>".$recipeTerm->name."</div></a> ";
$termChilds = get_term_children($recipeTerm->term_id, 'recipegroups' );
foreach($termChilds as $child){
$chTerm = get_term_by( 'id', $child, 'recipegroups');
$termLink =get_term_link( $chTerm );
echo "<a href='$termLink'><div class='top-cat-items'>".$chTerm->name."</div></a>";
}
echo "</div>"; // end of termsBox div
}
}
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