Javascript繼承和基類原型的問題

Question

我在繼承時遇到配置對象的問題，所以我已經

baseclass.prototype.activity =function(){ console.log("Im"+activity); }

以及其他繼承基類的其他對象（例如A和B）。

我想根據A和B的類型配置運行，因此，如果它是A，則調用run應該將活動設置為Running，並且與B類似，它可能會游泳我正在使用以下工廠方法根據類型創建A和B

activityFactoryObject.prototype.makeObj = Object.create(baseclass);
activityFactoryObject.prototype.createObject = function (config) {

    switch (config) {
    case "running":

        this.makeObj = A;
        break;
    case "swimming":

        this.makeObj = B;

        break;
    }
    this.makeObj.prototype = baseclass.prototype;  
    return new this.makeObj(config); 

};

Answer 1

我不確定您的目標是什么，但是如果它們都從baseClass繼承而來，唯一的區別是活動顯示的內容就足夠了：

baseClass.protoype.activity = function ( activity ) { console.log( "I'm " + activity ); };

var a = new BaseClass(),
    b = new BaseClass();

a.activity( 'Running' ); // -> "I'm Running"
b.activity( 'Swimming' ); // -> "I'm Swimming"

Answer 2

不確定這是否是您要的：

var Activity = function(argsObj){
  this.activityType = argsObj.activityType || "Default value";
};
Activity.prototype.doIt = function(){
  console.log("I am " + this.activityType);
};

var Run = function(argsObj){
  //re use Activity initializer
  Activity.apply(this,arguments);
};
Run.prototype=Object.create(Activity.prototype);
Run.prototype.constructor = Run;

var Swim = function(argsObj){
  //re use Activity initializer
  Activity.apply(this,arguments);
};
Swim.prototype=Object.create(Activity.prototype);
Swim.prototype.constructor = Swim;

function activityFactory(argsObj){
  return new window[argsObj.type](argsObj);
}

var r = activityFactory({type:"Run",activityType:"running"});
var s = activityFactory({type:"Swim",activityType:"swimming"});
r.doIt();//I am running
s.doIt();//I am swimming
console.log(r instanceof Run);//true
console.log(s instanceof Swim);//true
console.log(s instanceof Activity);//true
var wrong = activityFactory({type:"Run"});
wrong.doIt();//I am Default value

有關構造函數和原型的更多信息： https : //stackoverflow.com/a/16063711/1641941