[英]MYSQL query so it also returns values if has no value in the other table
[英]Query also returns column with value 0
我有兩個表:
tb_question
**id_quest** | **desc_quest**
1 | How do you do...?
2 | How are you...?
tb_answer
**id_quest** | **date_answer**
1 | 2013/11/25
1 | 2013/11/26
1 | 2013/11/27
而我的查詢:
SELECT
q.id_quest,
q.desc_quest,
COUNT(a.id_quest) as total_answer -- count total answer by question
FROM tb_question q
INNER JOIN tb_answer a
ON q.id_quest = a.id_quest;
結果:
ID_QUEST | DESC_QUEST | TOTAL_ANSWER
1 | How do you do...? | 3
如何返回還等於0的id = 2的問題?
預期結果:
ID_QUEST | DESC_QUEST | TOTAL_ANSWER
1 | How do you do...? | 3
2 | How are you...? | 0
兩個問題:
您必須使用外部聯接來獲取沒有答案的問題。
您忽略了GROUP BY
子句。
SELECT
q.id_quest,
q.desc_quest,
COUNT(a.id_quest) as total_answer
FROM tb_question q
LEFT OUTER JOIN tb_answer a ON q.id_quest = a.id_quest
GROUP BY q.id_quest
不要使用內部聯接來選擇所有idquest,使用內部聯接來產生表的子集
SELECT tbq.id_quest,tbq.desc_quest,COUNT(tba.id_quest) FROM tb_question tbq LEFT OUTER JOIN tb_answer tba ON tba.id_uest=tbq.id_quest GROUP BY tbq.id_quest ORDER BY tbq.id_quest
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