使用源代碼的bash腳本精心制作菜單

Question

我得到了這兩個腳本configScript.sh和genScript.sh ，它們完全可以按照我的要求工作。 configScript.sh設置了我genScript.sh在外殼中運行genScript.sh時使用的選項。

#!/bin/bash -x
#configScript.sh
func()
{
echo "
Choose
1 - Option 1
2 - Option 2
"
echo -n "   Enter selection: "
read select
case $select in
            1 ) 
            echo "  Option 1 chosen"
            . ./genScript.sh one
            cat << EOF >options.sh
OPTION=$OPTION
EOF
            ;;
            2 )
            echo "  Option 2 chosen"
            . ./genScript.sh two
            cat << EOF >options.sh
OPTION=$OPTION
EOF
            ;;

esac
}
func

---

#!/bin/bash -x
#genScript.sh
OPTION=""
. options.sh
[ "$1" ] && OPTION=$1
func2()
{
    if [ "$OPTION" == one ] ; then
        echo "Option one"
    elif [ "$OPTION" == two ] ; then
        echo "Option two"
    else
        echo "null"
    fi
}
func2   

---

我的問題是我想將configScript.sh菜單configScript.sh為如下所示：

---

#!/bin/bash -x
#configScript.sh
func()
{
echo "
Choose
1 - foo
2 - bar 
"
echo -n "   Enter selection: "
read select
case $select in
            1 ) 
            echo "  foo chosen"
            foo
            ;;
            2 )
            echo "  bar chosen"
            bar
            ;;      
esac
}

foo()
{
    echo "
    Choose
    1 - foo1
    2 - foo2
    "
    echo -n "    Enter Selection: "
    read fooSelect
    case $fooSelect in
        1 )
        echo "foo1 chosen"
        ;;
        2 )
        echo "foo2 chosen"
        ;;
    esac
}

bar()
{
        echo "
    Choose
    1 - bar1
    2 - bar2
    "
    echo -n " Enter Selection: "
    read barSelect
    case $barSelect in
        1 )
        echo "bar1 chosen"
        ;;
        2 )
        echo "bar2 chosen"
        ;;
    esac
}
func

---

我在哪里可以將所選的選項寫到options.sh ？ 這部分：

. ./genScript.sh one
cat << EOF >options.sh
OPTION=$OPTION
EOF

如果將它們保留在foo()和bar() ，則意味着如果我配置了回顯foo1然后回bar2我的genScript.sh應該只輸出其中之一。 我該如何解決？

更新*我將嘗試使其更加清晰。 如果我還沒有運行任何腳本，則options.sh將為空。 如果然后運行configScript.sh並選擇回顯foo2的選項，然后選擇bar1的選項，然后關閉'configscript.sh . After that I run . After that I run genScript.sh and I want it to echo foo2 and bar1`。

Answer 1

您的配置腳本：

#!/bin/bash -x
#configScript.sh
func()
{
    . options.sh
    echo "
    Choose
    1 - foo
    2 - bar 
    3 - update config
    "
    echo -n "   Enter selection: "
    read select
    case $select in
        1 ) echo "  foo chosen"    ; foo ;;
        2 ) echo "  bar chosen"    ; bar ;;      
        3 ) echo "  update chosen" ; update ;; 
    esac
}

update()
{
cat <<EOF >options.sh
FOO=$FOO
BAR=$BAR 
EOF

. ./genScript.sh
}

foo()
{
    echo "
    Choose
    1 - foo1
    2 - foo2
    "
    echo -n "    Enter Selection: "
    read fooSelect
    case $fooSelect in
        1 ) echo "foo1 chosen" ; FOO="foo1" ;;
        2 ) echo "foo2 chosen" ; FOO="foo2" ;;
    esac
}

bar()
{
    echo "
    Choose
    1 - bar1
    2 - bar2
    "
    echo -n " Enter Selection: "
    read barSelect
    case $barSelect in
        1 ) echo "bar1 chosen" ; BAR="bar1" ;;
        2 ) echo "bar2 chosen" ; BAR="bar2" ;;
    esac
}
func

您的genScript.sh

#!/bin/bash -x
#genScript.sh
FOO=""
BAR=""
. options.sh
[ "$1" ] && FOO=$1
[ "$2" ] && BAR=$2
func2()
{
    echo $FOO
    echo $BAR
}
func2