[英]Giving struct to function with pointers
在C語言中,我嘗試使用一種結構來存儲播放器的當前數據,並在結構中進行管理:
#include <stdio.h>
#include <stdlib.h>
typedef struct playerdat{
char playername[20];
int maxhp;
}playerdat;
void new_game(struct playerdat *player){
printf("Enter your character's name: \n");
scanf("%s", &player->playername);
player->playername = strcpy("Little", player->playername);
}
int main(){
struct playerdat player;
new_game(&player);
return 0;
}
一切工作正常,直到我嘗試更改該結構的元素。
錯誤消息顯示為: 錯誤:從'char *'類型分配為'char [20]'類型時,類型不兼容
您能給我示范一個如何在這里使用指針的例子嗎? 謝謝您的幫助!
scanf("%s", &player->playername);//don't need &
player->playername = strcpy("Little", player->playername);//you know,the memeber `playername` is a array,`playername` is the name of the array,so you can't modify the name of a array
不要在scanf上將char與&一起使用。
#include<stdio.h>
int main()
{
char name[20];
int age;
printf ("Enter your family name: ");
scanf ("%s",name); //notice here no &
printf ("Enter your age: ");
scanf ("%d",&age); // here comes &
return 0;
}
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