PHP，從（Mutli）多維數組獲取值
[英]PHP, Get values from (Mutli) Multidimensional Array
問題描述
我有一個多維數組，試圖從中使用foreach提取值。
它檢索為JSON格式，因此我使用json_decode將其轉換為關聯數組。
該數組包含各種產品的價格信息。 我正在努力解決的問題是，每個產品都包含多個嵌套數組。
因此，我不確定如何將其集成到foreach 。
數組$ arr：
Array
(
[result] => success
[totalresults] => 3
[products] => Array
(
[product] => Array
(
[0] => Array
(
[pid] => 2
[gid] => 2
[type] => other
[name] => Shared Hosting
[description] => Shared Cloud
[module] => custom server
[paytype] => onetime
[pricing] => Array
(
[GBP] => Array
(
[prefix] => £
[suffix] => GBP
[msetupfee] => 0.00
[qsetupfee] => 0.00
[ssetupfee] => 0.00
[asetupfee] => 0.00
[bsetupfee] => 0.00
[tsetupfee] => 0.00
[monthly] => 0.00
[quarterly] => -1.00
[semiannually] => -1.00
[annually] => -1.00
[biennially] => -1.00
[triennially] => -1.00
)
)
[customfields] => Array
(
[customfield] => Array
(
)
)
[configoptions] => Array
(
[configoption] => Array
(
[0] => Array
(
[id] => 2
[name] => Years
[type] => 2
[options] => Array
(
[option] => Array
(
[0] => Array
(
[id] => 2
[name] => 1 Year
[recurring] =>
[pricing] => Array
(
[GBP] => Array
(
[msetupfee] => 0.00
[qsetupfee] => 0.00
[ssetupfee] => 0.00
[asetupfee] => 0.00
[bsetupfee] => 0.00
[tsetupfee] => 0.00
[monthly] => 69.00
[quarterly] => 0.00
[semiannually] => 0.00
[annually] => 0.00
[biennially] => 0.00
[triennially] => 0.00
)
)
)
[1] => Array
(
[id] => 5
[name] => 2 Years
[recurring] =>
[pricing] => Array
(
[GBP] => Array
(
[msetupfee] => 0.00
[qsetupfee] => 0.00
[ssetupfee] => 0.00
[asetupfee] => 0.00
[bsetupfee] => 0.00
[tsetupfee] => 0.00
[monthly] => 138.00
[quarterly] => 0.00
[semiannually] => 0.00
[annually] => 0.00
[biennially] => 0.00
[triennially] => 0.00
)
)
)
[2] => Array
(
[id] => 8
[name] => 3 Years
[recurring] =>
[pricing] => Array
(
[GBP] => Array
(
[msetupfee] => 0.00
[qsetupfee] => 0.00
[ssetupfee] => 0.00
[asetupfee] => 0.00
[bsetupfee] => 0.00
[tsetupfee] => 0.00
[monthly] => 276.00
[quarterly] => 0.00
[semiannually] => 0.00
[annually] => 0.00
[biennially] => 0.00
[triennially] => 0.00
)
)
)
[3] => Array
(
[id] => 11
[name] => 4 Years
[recurring] =>
[pricing] => Array
(
[GBP] => Array
(
[msetupfee] => 0.00
[qsetupfee] => 0.00
[ssetupfee] => 0.00
[asetupfee] => 0.00
[bsetupfee] => 0.00
[tsetupfee] => 0.00
[monthly] => 552.00
[quarterly] => 0.00
[semiannually] => 0.00
[annually] => 0.00
[biennially] => 0.00
[triennially] => 0.00
)
)
)
[4] => Array
(
[id] => 14
[name] => 5 Years
[recurring] =>
[pricing] => Array
(
[GBP] => Array
(
[msetupfee] => 0.00
[qsetupfee] => 0.00
[ssetupfee] => 0.00
[asetupfee] => 0.00
[bsetupfee] => 0.00
[tsetupfee] => 0.00
[monthly] => 1104.00
[quarterly] => 0.00
[semiannually] => 0.00
[annually] => 0.00
[biennially] => 0.00
[triennially] => 0.00
)
)
)
)
)
)
)
)
)
對於每個產品ID（ [pid] ），從[product]重復了以上部分-我無法在帖子中容納整個數組，因此這里是指向該產品的鏈接-http://pastebin.com/0qgh5scG
我要實現的是將數組中每個產品ID [pid]的名稱描述和每個月的價格*放入其自己的數組中，並將該數組變量名關聯為[pid] 。
*（每月價格實際上是每年的價格，這只是模塊將數據存儲在數據庫中的一種怪異方式）
我已經嘗試過foreach ：
$arr = json_decode($jsondata, true); # Decode JSON String
foreach ($arr['products']['product'] as $num) {
$pid = $num['pid'];
$yearlycosts = $arr['configoptions']['configoption']['0']['options']['option'][0]['pricing']['GBP']['monthly'];
echo $pid;
echo $yearlycosts;
}
產品ID可以正常獲取，但是究竟如何為每個產品ID [pid]提取多個[name]和相關的多個[monthly]值？
我現有的foreach內是否需要一個foreach ？
最終，我想將這些值傳遞給新數組，每個數組都以其對應的[pid]值命名。 但是我認為這對我來說是一個單獨的問題/挑戰。
我希望以上已講得通。 我是數組的新手，在搜索大量示例時，沒有發現具有與上述數組一樣復雜的數組或具有唯一命名的節的數組。
2 個解決方案
解決方案1
1 已采納 2013-12-14 01:47:14
首先，這個$ pricing變量是從哪里來的？ 您最初使用的是$ num。
是的，只是一個嵌套的foreach循環就可以做到這一點：
$arr = json_decode($jsondata, true); # Decode JSON String
foreach ($arr['products']['product'] as $num) {
$pid = $num['pid'];
echo "Product ID: ".$pid."\n";
echo "Options: \n"
$i = 1;
foreach($num['configoptions']['configoption']['0']['options']['option'] as $option)
{
$name = $option['name'];
$yearlycosts = $option['pricing']['GBP']['monthly'];
echo " - Option ".$i.": ".$name." ($".$yearlycosts.")\n";
++$i;
}
}
解決方案2
0 2013-12-12 03:19:38
首先，看一下數組結構，“ CUSTOMFIELDS”只是一個空鍵，它不包含“ CONFIGOPTION”。
所以這：
echo $k['CUSTOMFIELDS'][CONFIGOPTIONS][CONFIGOPTION][OPTIONS][OPTION][NAME];
echo $k['CUSTOMFIELDS'][CONFIGOPTIONS][CONFIGOPTION][OPTIONS][OPTION][MONTHLY];
需要看起來像這樣：
echo $k[CONFIGOPTIONS][CONFIGOPTION][OPTIONS][OPTION][NAME];
echo $k[CONFIGOPTIONS][CONFIGOPTION][OPTIONS][OPTION][MONTHLY];
我想我可能會嘗試首先修復所有索引名稱，然后從那里使我的生活變得輕松。 我將使用此函數遍歷整個數組：
function traverseArray($array)
{
// Loops through each element. If element again is array, function is recalled. If not, result is echoed.
foreach($array as $key=>$value)
{
if (is_array($value))
{
traverseArray($value);
} else {
if (preg_match("/[0-9]/", $key) && !isset($array[preg_replace("[0-9]", "", $key)]))
$array[preg_replace("[0-9]", "", $key)] = $value;
}
}
}
此函數（在此處找到： http ： //snipplr.com/view/10200/ ，並針對當前問題進行了修改）將遍歷整個數組，包括每個級別，並且如果該鍵從數組末尾刪除數字沒有數字不存在。 原因是其中的某些數組包含多個帶有鍵的數組，如OPTION，OPTION12，OPTION43等。如果存在同一級別中沒有數字的鍵，則將其保留。 現在，所有數字都從諸如PRICING，GBP等鍵中移走了。我們只剩下一些OPTION鍵，這些鍵的末尾都有數字。 然后，我們將能夠：
traverseArray($arr); // Goes through arrray and removes random numbers unless not possible
foreach($k['CONFIGOPTIONS']['CONFIGOPTION']['OPTIONS'] as $option) {
echo $option['NAME'];
echo $option['PRICING']['GBP']['MONTHLY'];
}
試試看。 我認為應該可以。
PS：他們真的應該對API有所了解，因為這是一個可怕的數組。 沒有任何理由。
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