[英]Extract a String using RegEx
[0-6, 1-3][01-20, 22-23]22/123
從以上輸入中,我想摘錄以下文本。
0-6, 1-3
01-20, 22-23
22
123
以下代碼段提取了除第一個文本外的所需文本。
Pattern depArrHours = Pattern.compile("^(\\[(.+)\\]){2}(.+)\\/(.+)$");
Matcher matcher = depArrHours.matcher("[0-6, 1-3][01-20, 22-23]22/123");
if (matcher.matches()) {
System.out.println(matcher.group(0));
System.out.println(matcher.group(1));
System.out.println(matcher.group(2));
System.out.println(matcher.group(3));
System.out.println(matcher.group(4));
}
輸出:
[0-6, 1-3][01-20, 22-23]22/123
[01-20, 22-23]
01-20, 22-23
22
123
您能幫我修復正則表達式模式以提取第一部分嗎(0-6、1-3)?
您應該分別指定前兩個組中的每個組:
Pattern depArrHours = Pattern.compile("^(\\[(.+)\\])(\\[(.+)\\])(.+)\\/(.+)$");
嘗試模式
\\[([^\\]]*)\\]|(([0-9]*)/([0-9]*))
並與matcher.find()
Pattern depArrHours = Pattern.compile("\\[([^\\]]*)\\]|(([0-9]*)/([0-9]*))");
Matcher matcher = depArrHours.matcher("[0-6, 1-3][01-20, 22-23]22/123");
while (matcher.find()) {
String group = matcher.group(1);
if (group == null) {
// matched 22/123
System.out.println(matcher.group(3));
System.out.println(matcher.group(4));
} else {
// matched [0-6, 1-3] or [01-20, 22-23]
System.out.println(group);
}
}
產量
0-6, 1-3
01-20, 22-23
22
123
您可以嘗試指定每個(\\\\[(.+)\\\\])
而不是{2}
:
Pattern depArrHours = Pattern.compile("^(\\[(.+)\\])(\\[(.+)\\])(.+)\\/(.+)$");
Matcher matcher = depArrHours.matcher("[0-6, 1-3][01-20, 22-23]22/123");
if (matcher.matches()) {
System.out.println(matcher.group(0));
System.out.println(matcher.group(1));
System.out.println(matcher.group(2));
System.out.println(matcher.group(3));
System.out.println(matcher.group(4));
System.out.println(matcher.group(5));
System.out.println(matcher.group(6));
}
輸出:
[0-6, 1-3][01-20, 22-23]22/123
[0-6, 1-3]
0-6, 1-3
[01-20, 22-23]
01-20, 22-23
22
123
嘗試,
String input="[0-6, 1-3][01-20, 22-23]22/123";
String[] arr=input.replace('[', ' ').split("[\\]/]");
for (String string : arr) {
System.out.println(string.trim());
}
嘗試
String k ="[0-6, 1-3][01-20, 22-23]22/123";
Pattern p = Pattern.compile("\\[([^\\]]*)\\]|([0-9]*)/([0-9]*)");
Matcher m = p.matcher(k);
while(m.find()){
System.out.println((m.group(1)!=null)?m.group(1):m.group(2)+"\n"+m.group(3));
}
正則表達式\\\\[([^\\\\]]*)\\\\]|([0-9]*)/([0-9]*)
可以表示為
輸出 :
0-6, 1-3
01-20, 22-23
22
123
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