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[英]How to use a design pattern to arrange the file structure in a java+spring application
[英]How do I correctly use @PathVariable in Java+Spring?
我有一個控制器可以很好地處理其他請求映射,但是我很難@PathVariable
與@PathVariable
注釋一起使用。
在此示例中 (請參見“ URI模板模式”),它具有以下示例:
@RequestMapping(value="/owners/{ownerId}", method=RequestMethod.GET)
public String findOwner(@PathVariable String ownerId, Model model) {
Owner owner = ownerService.findOwner(ownerId);
model.addAttribute("owner", owner);
return "displayOwner";
}
我的代碼如下所示:
@RequestMapping( value="/ViewReport/json", method = RequestMethod.GET)
public ModelAndView TestJson(final Model model){
model.addAttribute("fnord", "{\"hello\":\"awesome\"}");
return new ModelAndView("reportViewJson");
}
@RequestMapping( value="/ViewReport/jayson/{foobar}", method = RequestMethod.GET)
public ModelAndView TestJayz(final Model model, @PathVariable String foobar){
model.addAttribute("fnord", "{\"hello\":\""+foobar+"\"}");
return new ModelAndView("reportViewJson");
}
然后,我有一個包含以下內容的web.xml
文件:
<servlet-mapping>
<servlet-name>autoreport</servlet-name>
<url-pattern>/ViewReport/jayson/*</url-pattern>
</servlet-mapping>
<servlet-mapping>
<servlet-name>autoreport</servlet-name>
<url-pattern>/ViewReport/json</url-pattern>
</servlet-mapping>
現在,當我導航到/ViewReport/json
,便得到了我所期望的JSON {"hello": "awesome"}
。 但是,當我導航到/ViewReport/jayson/42
我得到了
HTTP Status 404 -
type Status report
message
description The requested resource () is not available.
Apache Tomcat/7.0.29
我對PathVariable
使用有什么錯,我需要怎么做才能解決?
當我的服務器啟動時,它彈出以下行:
[ INFO] 14:15(AbstractUrlHandlerMapping.java:registerHandler:315)
Mapped URL path [/ViewReport/json.*] onto handler 'reportViewController'
[DEBUG] 14:15(AbstractBeanFactory.java:doGetBean:246)
Returning cached instance of singleton bean 'reportViewController'
[ INFO] 14:15(AbstractUrlHandlerMapping.java:registerHandler:315)
Mapped URL path [/ViewReport/json/] onto handler 'reportViewController'
[DEBUG] 14:15(AbstractBeanFactory.java:doGetBean:246)
Returning cached instance of singleton bean 'reportViewController'
[ INFO] 14:15(AbstractUrlHandlerMapping.java:registerHandler:315)
Mapped URL path [/ViewReport/jayson/{foobar}] onto handler 'reportViewController'
當我發出請求時,我得到了:
[DEBUG] 20:45(DispatcherServlet.java:doService:823)
DispatcherServlet with name 'autoreport' processing GET request for [/ViewReport/jayson/fnord]
[ WARN] 20:45(DispatcherServlet.java:noHandlerFound:1108)
No mapping found for HTTP request with URI [/ViewReport/jayson/fnord] in DispatcherServlet with name 'autoreport'
春天有魔力; 參數順序很重要。 嘗試反轉處理程序參數的順序。 代替這個:
public ModelAndView TestJayz(final Model model, @PathVariable String foobar)
嘗試這個:
public ModelAndView TestJayz(@PathVariable String foobar, final Model model)
采取2:
嘗試將web.xml中的映射更改為更通用的映射。 例如:
<servlet-mapping>
<servlet-name>autoreport</servlet-name>
<url-pattern>/ViewReport/*</url-pattern>
</servlet-mapping>
我在測試web.xml中使用了/spring/*
,在控制器中使用了@RequestMapping(“ / blammy / {value}”),然后將請求發送至“ {WEBROOT} / spring / blammy / testvalue”,其中“ {WEBROOT} ”是我的測試應用的網絡根目錄。
請求映射相對於調度程序Servlet映射的相對關系(默認情況下,請參閱DefaultAnnotationHandlerMapping
和AnnotationMethodHandlerAdapter
alwaysUseFullPath
屬性以獲取更多信息)。
如果您請求資源/ViewReport/jayson/fnord
spring mvc正在尋找映射到fnord
的處理程序。
您需要請求/ViewReport/jayson/ViewReport/jayson/fnord
您是否嘗試過@PathVariable(value =“ foobar”)字符串foobar ?
@RequestMapping( value="/ViewReport/jayson/{foobar}", method = RequestMethod.GET)
public ModelAndView TestJayz(final Model model, @PathVariable(value="foobar") String foobar){
model.addAttribute("fnord", "{\"hello\":\""+foobar+"\"}");
return new ModelAndView("reportViewJson");
}
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